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denis-greek [22]
9 months ago
10

F(x) = 2x + 3g(x) = 2x² + 6x + 13Find: (gºf)(x)

Mathematics
1 answer:
Butoxors [25]9 months ago
5 0

Answer:

The function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

Explanation:

Given the functions;

\begin{gathered} f(x)=2x+3 \\ g(x)=2x^2+6x+13 \end{gathered}

Solving for the function;

(g\circ f)(x)=g(f(x))

so, we have;

\begin{gathered} g(f(x))=2(f(x))^2+6(f(x))+13 \\ g(f(x))=2(2x+3)^2+6(2x+3)+13 \\ g(f(x))=2(4x^2+12x+9)^{}+6(2x)+6(3)+13 \\ g(f(x))=8x^2+24x+18^{}+12x+18+13 \\ g(f(x))=8x^2+24x^{}+12x+18+18+13 \\ g(f(x))=8x^2+36x+49 \end{gathered}

Therefore, the function (gof)(x) is;

(g\circ f)(x)=8x^2+36x+49

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Which equation has the solutions X=1 +-SQRT 5?
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Answer:

D is correct. x^2-2x-4=0

Step-by-step explanation:

We are given the root of the equation

x=1+\pm \sqrt{5}

If we are given solution of the equation then find equation using formula.

If a and b are the solution of equation then equation would be (x-a)(x-b)=0

Here, a=1+\sqrt{5} , b=1-\sqrt{5}

Equation form would be (x-1-\sqrt{5})(x-1+\sqrt{5})=0

Now we simplify the above equation to get correct option.

x^2-x+x\sqrt{5}-x+1-\sqrt{5}-x\sqrt{5}+\sqrt{5}-5=0

x^2-2x-4=0

So, D is correct.  x^2-2x-4=0

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3 years ago
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Step-by-step explanation:

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2 years ago
Dr.Lamb is mixing a solution for his next patient. He has a cylindrical test tube which is 4 inches across on the inside. The de
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Answer:  There are 34.35 liters left in the test tube.

Step-by-step explanation:

Since we have given that

Depth of the tube = 9 inches

Circumference of base=4 inches

As we know the formula of circumference ,

Circumference=2\pi r\\\\4=2\times \frac{22}{7}\times r\\\\4\times{7}{22\times 2}=r\\\\\frac{7}{11}=r

Now, we need to find the volume of tube is given by

\text{ Volume of test tube }=\pi r^2h\\\\\text{ Volume of test tube }=\frac{22}{7}\times \frac{7}{11}\times \frac{7}{11}\times 9\\\\\text{ Volume of test tube }=\frac{126}{11}=11.45\ inches^3

Since we have also given that,

Of 1 cubic inch of space holds 3 liters of water,

So,

1\text{ cubic inch}=3\text{ liters}\\\\11.45\text{ cubic inches}=3\times 11.45=34.35\text{ liters}

Hence, there are 34.35 liters left in the test tube.



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