A+b+c=130
a,b,c ip cu 2,3,4
2a=3b=4c=k
a=k/2
b=k/3
c=k/4
k/2 + k/3+ k/4= 130 aducem la acelasi numitor (12)
6k+4k+3k=1560
13k=1560
k=120
a=120/2=60
b=120/3=40
c=120/4=30
I believe the answer is 7x-y
I think the answer would be 38in^2
Because the equation is : (a+b) *h / 2
A and b are both the bases of the trapezium
So (11 + 8) these are the bases and the height is 4 so you would do
(11+8)*4 / 2
(19)*4 / 2
76 / 2
= 38
Answer:
A
Step-by-step explanation: