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Genrish500 [490]
3 years ago
15

Pls help i don't under stand

Mathematics
1 answer:
Monica [59]3 years ago
5 0

Answer:

for level 1: x=36

because you just need to do 180-144

for level 2: x = 127

you can just so 180-15-38

for level 3: x = 36

because you start by setting an equation like this:

92 + (2x+16) = 180

subtract 92 from both sides, then subtract 16 from both sides, and finally divide both sides by 2 to get 36

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If j(x)=3x+1, find x if j(x)=-11​
vladimir1956 [14]

Answer:

x = -4

Step-by-step explanation:

Step 1: Define

j(x) = 3x + 1

j(x) = -11

Step 2: Substitute and solve for <em>x</em>

-11 = 3x + 1

-12 = 3x

x = -4

6 0
3 years ago
Find the median of 30 , 40, 35, 50 and 55 degrees angle measures
ELEN [110]
We know that
the median <span>is the middle number when listed in order from least to greatest.
</span>
step 1
listed in order from least to greatest
[<span>30,40, 35, 50, 55]--------> [30, 35, 40, 50, 55]

step 2
find the middle number

the middle number is 40

therefore

the answer is
the median is 40</span>°<span>

</span>
6 0
3 years ago
At the start of the week, Ladasha’s checking account had a balance of $34. She deposited $50 each day for three days. She made a
Rama09 [41]
34 + 50 *3 - 60+22 hope this helps out
5 0
3 years ago
Read 2 more answers
Pleas yall help ill give you brainiest if you help
Snowcat [4.5K]

Answer:

C) $3557.75

Step-by-step explanation:

First...

Use the equation SI = PRT/100 or (simple intrust is equal to principle*rate*time divided by 100).

(53500*13.3*0.5)/100

Next...

Mutiply

355775/100

Finally...

Divide

355775/100 = 3557.75

So the answer is...

$3557.75

4 0
3 years ago
Cesar invests $8200 in two different accounts. The first account paid 13 %, the second account paid 2 % in interest. At the end
Ugo [173]

a = amount invested at 13%

b = amount invested at 2%

we know the total amount invested is 8200, so if the first amount is say "a", the second amount must be the slack left from subtracting "a", namely b = 8200 - a.

we also know 13% of "a" plus 2% of "b" yielded an interest of $461 in a year.

\bf \begin{array}{|c|ll} \cline{1-1} \textit{a\% of b}\\ \cline{1-1} \\ \left( \cfrac{a}{100} \right)\cdot b \\\\ \cline{1-1} \end{array}~\hspace{5em}\stackrel{\textit{13\% of a}}{\left( \cfrac{13}{100}\right)a\implies 0.13a}~\hfill \stackrel{\textit{2\% of b}}{\left( \cfrac{2}{100} \right)b\implies 0.02b} \\\\[-0.35em] ~\dotfill

\bf \stackrel{\textit{sum of the percentages}}{0.13a+0.02b}~~=~~\stackrel{\textit{yield for 1 year}}{461}\implies 0.13a+0.02\left(\boxed{8200-a} \right) = 461 \\\\\\ 0.13a+164-0.02a=461\implies 0.11a+164=461\implies 0.11a=297 \\\\\\ a = \cfrac{297}{0.11}\implies \blacktriangleright a = 2700 \blacktriangleleft ~\hfill b = 8200-2700\implies \blacktriangleright b = 5500 \blacktriangleleft

3 0
4 years ago
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