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vredina [299]
3 years ago
10

What is the intersection of y=-x+8

Mathematics
2 answers:
san4es73 [151]3 years ago
5 0
(0,8) on the y axis and (8,0) on the x axis.

Hope this helps if so feel free to give me a brainliest!!!


Have a wonderful day :)
Effectus [21]3 years ago
5 0
Y - (0,8) and x - (8,0)
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How can we recognize a proportional relationship when looking at a table or a set of ratios?
anygoal [31]
Proportional Numbers should be in a straight line on a plot when graphed out
7 0
3 years ago
For problems 12 - 14, Determine whether each sequence appears to be an
marshall27 [118]

Step-by-step explanation:

⇒12)It is an arithmetic sequence.

   d=2-1=3-2=4-3=1

    a(n) = a +(n-1)d

    a(n) = 1+(n-1)1

The next three terms:

a(6) = 1+(6-1)1=6

a(7) = 1+(7-1)1=7

a(8) = 1+(8-1)1=8

⇒13)It is an arithmetic sequence.

   d=0-3=-3-0=-6+3=-3

    a(n) = a +(n-1)d

    a(n) = 3+(n-1)-3

The next three terms:

a(5) = 3+(5-1)-3=-9

a(6) = 3+(6-1)-3=-12

a(7) = 3+(7-1)-3=-15

⇒14)It is <u>not </u>an arithmetic sequence.

⇒15) a(50) = 10 +(50-1)5

                  =<u>255</u>

<u>I hope this helps</u>

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8 0
3 years ago
Indicate the equation of the given line in standard form. Show all your work for full credit. the line containing the median of
alukav5142 [94]

Answer:

* The equation of the median of the trapezoid is 10x + 6y = 39

Step-by-step explanation:

* Lets explain how to solve the problem

- The slope of the line whose end points are (x1 , y1) , (x2 , y2) is

  m=\frac{y_{2}-y_{1}}{x_{2}-x_{1}}

- The mid point of the line whose end point are (x1 , y1) , (x2 , y2) is

  (\frac{x_{1}+x_{2}}{2},\frac{y_{1}+y_{2}}{2})

- The standard form of the linear equation is Ax + BC = C, where

  A , B , C are integers and A , B ≠ 0

- The median of a trapezoid is a segment that joins the midpoints of

 the nonparallel sides

- It has two properties:

# It is parallel to both bases

# Its length equals half the sum of the base lengths

* Lets solve the problem

- The trapezoid has vertices R (-1 , 5) , S (! , 8) , T (7 , -2) , U (2 , 0)

- Lets find the slope of the 4 sides two find which of them are the

 parallel bases and which of them are the non-parallel bases

# The side RS

∵ m_{RS}=\frac{8-5}{1 - (-1)}=\frac{3}{2}

# The side ST

∵ m_{ST}=\frac{-2-8}{7-1}=\frac{-10}{6}=\frac{-5}{3}

# The side TU

∵ m_{TU}=\frac{0-(-2)}{2-7}=\frac{2}{-5}=\frac{-2}{5}

# The side UR

∵ m_{UR}=\frac{5-0}{-1-2}=\frac{5}{-3}=\frac{-5}{3}

∵ The slope of ST = the slop UR

∴ ST// UR

∴ The parallel bases are ST and UR

∴ The nonparallel sides are RS and TU

- Lets find the midpoint of RS and TU to find the equation of the

 median of the trapezoid

∵ The median of a trapezoid is a segment that joins the midpoints of

   the nonparallel sides

∵ The midpoint of RS = (\frac{-1+1}{2},\frac{5+8}{2})=(0,\frac{13}{2})

∵ The median is parallel to both bases

∴ The slope of the median equal the slopes of the parallel bases = -5/3

∵ The form of the equation of a line is y = mx + c

∴ The equation of the median is y = -5/3 x + c

- To find c substitute x , y in the equation by the coordinates of the

  midpoint of RS  

∵ The mid point of Rs is (0 , 13/2)

∴ 13/2 = -5/3 (0) + c

∴ 13/2 = c

∴ The equation of the median is y = -5/3 x + 13/2

- Multiply the two sides by 6 to cancel the denominator

∴ The equation of the median is 6y = -10x + 39

- Add 10x to both sides

∴ The equation of the median is 10x + 6y = 39

* The equation of the median of the trapezoid is 10x + 6y = 39

7 0
4 years ago
Use the properties of logarithms to write the following expression as one logarithm.
raketka [301]

Answer:

Step-by-step explanation:

hi! the log properties say that when logs are multiplied as log(xy), they can be expanded and added like log(x)+log(y). when logs are divided like log(x/y), they can be expanded as log(x)-log(y). when the log has an exponent like log(x^y), the exponent can be added to the front of the log like ylog(x). we can use these properties for this problem.

ln(x^3)+ln(y^2)-ln((x+1)^4)

ln(x^3*y^2)-ln((x+1)^4)

ln(\frac{(x^3y^2)}{((x+1)^4)})

6 0
3 years ago
Helpp me please!!!!!!
Alexeev081 [22]

Answer:

a. Inscribed angle = <WXY

b. Minor arc = arc(XY)

c. VWX

d. m(VWX) = 180°

e. m<VUW = 110°

Step-by-step explanation:

a. The angle, <WXY has its vertex on the circumference of the circle. Therefore, it can be referred to as an inscribed angle of the circle with center U.

Inscribed angle = <WXY

b. Arc(XY) is a minor arc because it is smaller than half of circle with center U.

Minor arc = arc(XY)

c. A semicircle is half of a full rotation for a circle. From the diagram, a semicircle is VWX

d. m(VWX) = Half the rotation of a full circle = 180°

e. m<VUW = arc(VW) (measure of central angle = measure of arc)

m<VUW = 110° (Substitution)

3 0
3 years ago
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