The nickels in the envelope is $0. 12
<h3>How to determine the number</h3>
From the information given, we have that;
Dimes + nickels = $1. 20
1/4 dimes + dimes = $ 1. 35
Let dimes = d
Nickels = n
d + n = 1. 20 equation a
d/4 + d = 1. 35 equation b
Make 'd' subject from equation a
d = 1. 20 - n
Substitute into equation b
1. 20 - n/ 4 + 1. 20 - n = 1. 35
0. 3 - 0. 25n + 1. 20 - n = 1. 35
collect like terms
- 1. 25n = 1. 35 - 1. 5
- 1. 25 = - 0. 15
n = -0. 15/ -1. 25
n = 0. 12
Thus, the number of nickels in the envelope is $0. 12
Learn more about algebraic expressions here:
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4 x^2 + 28 x + 49 = 0
Divide both sides by 4:
x^2 + 7 x + 49/4 = 0
Write the left hand side as a square:
(x + 7/2)^2 = 0
Take the square root of both sides:
x + 7/2 = 0
Subtract 7/2 from both sides:
Answer: x = -7/2
If it’s X-27=62, you have to isolate X. So you would put your -27 on the other side but in doing that you have to change your negative 27 to a positive as it is switching sides. So it would now be, X=62+27, which is 89. Final answer, X=89
The answer would be 120 hope this helps!!
Answer:
The exact is 1/339 or.00294985 but rounded it’s 1
Step-by-step explanation:
