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maw [93]
3 years ago
11

At what values of x, does f(x) = 0?

Mathematics
1 answer:
Alex3 years ago
8 0

Answer:

C. 4,   D. 2,   A. -1

Step-by-step explanation:

On the graph, the points at 0 are 4, 2,  and -1.

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PLEASE HELP Alice's freezer can be set to a range of temperatures, from
VMariaS [17]
I think it is B, but I'm not fully sure.

7 0
3 years ago
Which label on the cone below represents the center of the base?<br> D<br> B<br> Ο Α<br> OB
Firlakuza [10]

Answer:

C

Step-by-step explanation:

The center of the base is the center of the circle

The center of the circle is C

8 0
2 years ago
What is the common ratio for the geometric sequence?
Bezzdna [24]

Answer:

3 is the correct answer

u can find common ratio by dividing a specific term in GP by its preceding term. ...just as here

4/(4/3) = 3

also 12/4 = 3

also 36 /12 = 3

hence the common ratio for this GP is 3

hope it helped

Step-by-step explanation:

6 0
2 years ago
I'll mark brainliest just tell me how to.
IRINA_888 [86]

Answer:

a = 12

b = 2

c = 11

Step-by-step explanation:

\frac{( {x}^{5}y  {z}^{4} )^{3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{5 \times 3}y^{3}   {z}^{4 \times 3} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ \frac{ {x}^{15}y^{3}   {z}^{12} }{ {x}^{3} yz}  =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\  {x}^{15 - 3}  {y}^{3 - 1}  {z}^{12 - 1} =  {x}^{a}  {y}^{b}  {z}^{c} \\  \\  {x}^{12}  {y}^{2}  {z}^{11} =  {x}^{a}  {y}^{b}  {z}^{c}  \\  \\ equating \: like \: terms \: from \: both \: sides \\  \\  {x}^{12}  =  {x}^{a}  \:  \implies \: a = \boxed{ 12}\\  \\  {y}^{2}  =  {y}^{b}  \:  \implies \: b = \boxed{ 2} \\  \\  {z}^{11}  =  {z}^{c}  \:  \implies \: c = \boxed{ 11}

3 0
3 years ago
Suppose you decided to keep flipping a coin until tails came up, at which
MAVERICK [17]

Answer:

B. 6.3%

Step-by-step explanation:

For each time that the coin is tosse, there are only two possible outcomes. Either it comes up tails, or it does not. The probability of coming up tails on a toss is independent of any other toss. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

In which C_{n,x} is the number of different combinations of x objects from a set of n elements, given by the following formula.

C_{n,x} = \frac{n!}{x!(n-x)!}

And p is the probability of X happening.

Fair coin:

Equally as likely to come up heads or tails, so p = 0.5

Probability that the first tails comes up on the 4th flip of the coin?

0 tails during the first three, which is P(X = 0) when n = 3.

Tails in the fourth, with probability 0.5. So

p = 0.5P(X = 0)

P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}

p = 0.5P(X = 0) = 0.5*(C_{3,0}.(0.5)^{0}.(0.5)^{3}) = 0.0625

0.0625 * 100 = 6.25%

Rounding to the nearest tenth of a percent, the correct answer is:

B. 6.3%

4 0
3 years ago
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