Answer:
Step-by-step explanation:
Two ∆s can be considered to be congruent to each other using the Side-Angle-Side Congruence Theorem, if an included angle, and two sides of a ∆ are congruent to an included angle and two corresponding sides of another ∆.
∆ABC and ∆DEF has been drawn as shown in the attachment below.
We are given that 
and also 
.
In order to prove that ∆ABC 
∆DEF using the Side-Angle-Side Congruence Theorem, an included angle which lies between two known side must be made know in each given ∆s, which must be congruent accordingly to each other.
The included angle has been shown in the ∆s drawn in the diagram attached below.
Therefore, the additional information that would be need is:
Answer:
I can only help with 5 and 6 which both are A.
Explanation:
that's because Cosine is adjacent to the angle (the angle being 30 degrees and the side next to it is 43mm) divided by the hypotenuse (longest side of a right triangle. The 50 mm). A way you can remember the sin, cosine and tangent is SOH CAH TOA. Sine=opposite over hypotenuse, Cosine = adjacent over hypotenuse, Tangent = opposite over adjacent. For the next one, it is the same principal. X is adjacent to 22 degrees and the other number is the hypotenuse so it has to be Cosine.
Answer: z = 
Step-by-step explanation:
To find <em>z</em>, you must set up a proportion to solve.
To find the altitude of a special right triangle, the formula is:
You can use <em>5</em> as <em>a</em> and <em>2</em> as <em>b</em> to complete the proportion:
Next, to solve:
<u>Step 1</u>: Cross-multiply.
(5)*(2) = z*z
10 = z²
<u>Step 2</u>: Take square root.
10 = z²
√10 = z
I hope this helps!
Answer:
1.5 seconds
Step-by-step explanation:
i took a test with the same question
