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ANTONII [103]
3 years ago
12

2. Which statement is not true in the equation

Mathematics
1 answer:
Oduvanchick [21]3 years ago
7 0

Answer:

B

Step-by-step explanation:

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According to the article "Fatigue Testing of Condoms" (Polymer Testing, 2009: 567–571), "tests currently used for condoms are su
daser333 [38]

Answer:

99% Confidence interval:  (1196,1973)

Step-by-step explanation:

We are given the following in the question:

Sample size, n = 20

Mean, μ = 1584

Standard Deviation, σ = 607

99% Confidence interval:  

\bar{x} \pm t_{critical}\displaystyle\frac{s}{\sqrt{n}}  

Putting the values, we get,  

t_{critical}\text{ at degree of freedom 19 and}~\alpha_{0.01} = \pm 2.86  

1584 \pm 2.86(\dfrac{607}{\sqrt{20}} )\\\\ = 1584 \pm 388.18\\ = (1195.82 ,1972.18)\\ \approx (1196,1973)

Thus, there is a 99% chance that it will break in approximately 1196 to 1972

6 0
3 years ago
What is the equation of line JK in standard form?
natali 33 [55]
You need a little more information. Take a picture of the oroblem
3 0
3 years ago
Which expression is equivalent to g -m power divided by g to the n power
SOVA2 [1]

10 geydyduduwwjhwheyrtryyeueuwuwuueueuejjejeje

3 0
3 years ago
Identify the range of values for x.
Harlamova29_29 [7]

Answer:   Overall, the steps for algebraically finding the range of a function are:

Write down y=f(x) and then solve the equation for x, giving something of the form x=g(y).

Find the domain of g(y), and this will be the range of f(x). ...

If you can't seem to solve for x, then try graphing the function to find the range.

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
You know that a number 8 less than 60 is the number 52. so, you could rewrite your answer from the previous part as, "what numbe
svetoff [14.1K]
I'm a little confused by your question. 

You said 60-8 = 52 which is true.

Then, you asked 4x = 52 in an integer form
                           x = 52/4
                           x = 13. (Is that what you're asking?)

I'm not sure if this helps, but please comment if you need any help! Hope this helps though! :D
4 0
4 years ago
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