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gregori [183]
3 years ago
13

(DONT ANSWER IF YOU DONT KNOW)can any help on this?

Mathematics
1 answer:
Debora [2.8K]3 years ago
4 0

Answer:

4a) (1,9)

Step-by-step explanation:

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Find the value of :[5x+y+z][5x+y+z][5x+y+z]
KIM [24]

Answer:

Step-by-step explanation:

(a + b + c)³ = a³ + b³ + c³ + 3a²b + 3a²c + 3ab² + 3cb² +3 ac² + 3bc² + 6abc

a = 5a  ;  b =y   ; c = z

(5x + y + z)(5z + y + z )(5z + y +z) = (5x + y +z)³

= (5x)³ + y³ +z³ + 3(5x)²y + 3(5x)²z + 3(5x)*y² + 3*z*y² + 3*5x*z² + 3*y*z² + 6*5x*y*z

= 125x³ + y³ +z³ + 3*25x²y + 3*25x²*z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz

= 125x³ + y³ + z³ + 75x²y + 75x²z + 15xy² + 3zy² + 15xz² + 3yz² + 35xyz

6 0
3 years ago
Factor the Following:<br><br>1.) 8<br>2.) -12<br>3.) -3y²<br>4.) 6x²+36x<br>5.) 7x -14x²​
Alex787 [66]

Answer:

1.) 8 = 8

2.) -12 = -12

3.) -3y² = -3y²

4.) 6x² + 36x = 6x(x + 6)

5.) 7x - 14x² = 7x(1 - 2x)

~

3 0
3 years ago
23,697 round to the nearest ten thousand
CaHeK987 [17]
20,000 would be the answer
8 0
3 years ago
Plz do question 8 asap
RideAnS [48]
It's D, hope I helped ;)
8 0
3 years ago
Find all values of x in the interval [0, 2π] that satisfy the equation. <br><br>6sin²(x) = 3
34kurt

Answer:

The solutions are π/4, 3π/4,5π/4,7π/4

Step-by-step explanation:

The given equation is

6sin²(x) = 3

Divide by 6 to get:

{ \sin}^{2} (x) =  \frac{1}{2}

This implies that;

\sin(x) = \pm  \frac{ \sqrt{2} }{2}

If

\sin(x) = \frac{ \sqrt{2} }{2}

x =  \frac{\pi}{4}

in the first quadrant

x =  \frac{3\pi}{4}

in the second quadrant.

If

\sin(x) = -  \frac{ \sqrt{2} }{2}

x =  \frac{5\pi}{4}

in the third quadrant

x =  \frac{7\pi}{4}

5 0
3 years ago
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