2/3-1/4=5/12
You could make the denominators common by finding the GCF
The GCF of 4 and 3 is 12
This means that 8/12-3/12 which would give you 5/12.
:)
A horizontal asymptote y = a is a horizontal line which a curve approaches as x approaches positive or negative infinity. If the limit of a curve as x approaches either positive or negative infinity is a, then y=a is a horizontal asymptote.
A vertical asymptote x = b is a vertical line that a curve approaches but never crosses. The value b is not in the domain of the curve. More precisely if the limit of a curve as x approaches b is either positive or negative infinity then x=b is a vertical asymptote.
An oblique asymptote is a diagonal line (a line whose slope is either positive or negative) that a curve approaches. For a rational function R(x) = P(x) / Q (x) an oblique asymptote y = my + b is obtained by dividing P(x) by Q (x). Doing so will yield a quotient and remainder. If we set the quotient equal to y that gives the equation of the oblique asymptote.
Savings account, retirement savings, value of second car, balance in checking account i believe those are the only ones not positive though
Answer:
the two positive consecutive integers are 4 and 6.
Step-by-step explanation:
Let the smaller integer be s; then s^2 = (s + 2) + 10.
Simplifying, s^2 - s - 2 - 10 = 0, or
s^2 - s - 12 = 0.
Solve this by factoring: (s - 4)(s + 3) = 0.
Then s = 4 and s = -3.
If the first even integer is 4, the next is 6. We omit s = -3 because it's not even.
The smaller integer is 4. Does this satisfy the equation s^2 = (s + 2) + 10?
4^2 = (4 + 2) + 10 True or False?
16 = 6 + 10 = 16.
True.
So the two positive consecutive integers are 4 and 6.
Answer:
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Step-by-step explanation:
