If we have a triangle with sides a and b and an included angle of C, then the area of the triangle would be:
A = (1/2) ab sin C
If angle C is bisected into two each angles each measuring x, then the area can be expressed as:
A = (1/2) ab sin 2x
Using the trigonometric identity for sin 2x = 2 sin x cos x, the area would now be:
A = ab sin x cos x
Since the line segment s divides the angle into two, it also divides the triangle into two. Another equation for the area is:
A = (1/2) as sin x + (1/2) bs sin x
Equating the two equations gives us:
ab cos x = (1/2) as + (1/2) bs
Solving for s
s = 2 ab cos x / (a + b)
Answer: veasy
Step-by-step explanation: it is a rectangle then it's area will be length *breadth =45cm*26=1170cm^2.
I think the answer is 5 hope this helps
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Answer:
Step-by-step explanation:
To solve this problem, we must add up all the side values.
Our equation for the perimeter will look like:
Now lets plug in our values for our sides and solve:
Now lets combine like terms:
So this is our perimeter!
Hope this helps! :3