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Mnenie [13.5K]
2 years ago
5

What is the bottom answers?

Mathematics
2 answers:
omeli [17]2 years ago
4 0
Your picture doesn’t load
Verdich [7]2 years ago
4 0
Yea ur picture don’t load but I would help if I could sorryyyy!!!
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If you were given the function y=4x-3 and you had to find the Range, given the Domain: (1,3,5,7)
AysviL [449]

Answer:

option 4

Step-by-step explanation:

y = 4x-3

y = 4(1)-3

y = 1

y = 4(3)-3

y = 9

y = 4(5)-3

y = 17

y = 4(7)-3

y = 25

4 0
2 years ago
Find the area of the rug. DO NOT ROUND.<br><br> what is the area?
Mademuasel [1]

Answer:

\frac{198}{7} \ \text{feet}^{2}

<h3>Step-by-step explanation:</h3>

<u>Given:</u>

  • Diameter of rug = 6 feet

To find the area of the rug, we need to use the formula "πr² or π(D/2)²"

<u>Where:</u>

  • r = radius
  • d = diameter

Since we do not have the radius, we need to substitute the diameter in the formula "π(D/2)²" to determine the area of the rug.

⇒ \pi (\frac{D}{2} )^{2}

⇒ \pi (\frac{6}{2} )^{2}

⇒ \pi (3 )^{2}

⇒ \pi (3 )(3)

⇒ 9\pi

Substituting "22/7" as π:

⇒ 9(\frac{22}{7} )

⇒ (\frac{198}{7} )

When finding the area of ANY shape, do not forget to include the units.

⇒ \frac{198}{7} \ \text{feet}^{2}

4 0
2 years ago
Read 2 more answers
Suppose that Prudie earns the same each day.write an inequality to find how much she needs to earn each day
Sedbober [7]

let the amount of money earned by Prudie be p

since she earns the same amount of money each day after two days she has earned 2p

therefore the amount of money she needs  to earn each day equals p\geq0

3 0
3 years ago
You are told that P(A | B) = P(B | A). Which statement below must be true?
Katen [24]
The best answer to the question that is being stated above would be that A and B are both dependent. If I was told that P(A | B) = P (B | A), then the true statement is that both variables inside would be dependent upon each other, no matter if you exchange their places with one another.
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3 years ago
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Need help a through d
kobusy [5.1K]

it seems pretty tricky

7 0
3 years ago
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