Answer:
Option c, A square matrix
Step-by-step explanation:
Given system of linear equations are
Now to find the type of matrix can be formed by using this system
of equations
From the given system of linear equations we can form a matrix
Let A be a matrix
A matrix can be written by
A=co-efficient of x of 1st linear equation co-efficient of y of 1st linear equation constant of 1st terms linear equation
co-efficient of x of 2st linear equation co-efficient of y of 2st linear equation constant of 2st terms linear equation
co-efficient of x of 3st linear equation co-efficient of y of 3st linear equation constant of 3st terms linear equation 
which is a matrix.
Therefore A can be written as
A= ![\left[\begin{array}{lll}3&-2&-2\\7&3&26\\-1&-11&46\end{array}\right] 3\times 3](https://tex.z-dn.net/?f=%5Cleft%5B%5Cbegin%7Barray%7D%7Blll%7D3%26-2%26-2%5C%5C7%263%2626%5C%5C-1%26-11%2646%5Cend%7Barray%7D%5Cright%5D%203%5Ctimes%203)
Matrix "A" is a 
matrix so that it has 3 rows and 3 columns
A square matrix has equal rows and equal columns
Since matrix "A" has equal rows and columns Therefore it must be a square matrix
Therefore the given system of linear equation forms a square matrix
Hello from MrBillDoesMath!
Answer:
x = 1/2 (1 +\- i sqrt(23))
Discussion:
x \3x - 2 = (x/3)*x - 2 = (x^2)/3 - 2 (*)
1 \3x - 4 = (1/3)x - 4 (**)
(*) = (**) =>
(x^2)/3 -2 = (1/3)x - 4 => multiply both sides by 3
x^2 - 6 = x - 12 => subtract x from both sides
x^2 -x -6 = -12 => add 12 to both sides
x^2-x +6 = 0
Using the quadratic formula gives:
x = 1/2 (1 +\- i sqrt(23))
Thank you,
MrB
Answer:
-24+12(d-3)+22=-24+34(d-3)
10(d-3)
10d=-30
d=-30/10
d=3
Answer:
The probability is 
Step-by-step explanation:
The game of roulette wheel consists in spinning a wheel with 38 slots : 18 red, 18 black and 2 green.
If we suppose that the roulette is a fair roulette, then each slot has an equal chance of capturing the ball and given that the ball lands in a red, black or green slot this event doesn't give us information about the following spin. Meaning that exists independence between each spin of the roulette wheel.
In our exercise, we spin the roulette wheel 3 consecutive times and each time the ball lands in a red slot. This doesn't give us information about the fourth spin (because of the independence).
Given that each slot has an equal chance of capturing the ball we can calculate the probability of the ball landing on a red slot on the next spin as :
We divide the favourable cases (18 red slots) by the total cases (38 slots) in order to calculate the probability.
The probability is
