All categories

3 years ago

It the ratio 35 to 10 proportional to the ratio 7 to 5

Mathematics

1 answer:

ipn [44]3 years ago

4 0

Response:

35 : 10 = 7 : 2

Therefore 35 : 10 ≠ 7 : 5

You might be interested in

HELP ME PLEASE I REALLY NEED HELP!? :(

Aleksandr [31]

Just answers since long and many simplifiction
it's like doing those multiplication memory things that had like 100 questions but now with algebra fractions

5. fourth or $\frac{5x-15}{x^{2}-3x-28}$
6. third or $\frac{4x+25}{x^{2}+5x+4}$
7.the answe ris x+3 since it can be factored out of the 5x+15 tingie (second )
8. fourth or $\frac{x^{2}+4x}{4}$
9. fourth or $\frac{2y+6}{9y-7}$ times $\frac{3}{2}$
10. third or $\frac{(x+3)(x+8)}{(x-8)(x-8)}$
11. second or $\frac{x-5}{x-4}$
12. third or 11(x+7)=60

5 0

3 years ago

Marcos purchased a sail boat for $56,900. He anticipates each year the boat will decrease in value by 8.1% from the previous yea

Varvara68 [4.7K]

Answer: $56,900\left( 0.919\right)^x$

Step-by-step explanation:

Given

Marcos purchased a sailboat for $\$56,900$

Each year the boat will decrease in value by $8.1\%$

After 1 year it is

$\Rightarrow 56,900-56,900\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\\$

after another year it becomes

$\Rightarrow 56,900\left( 1-0.081\right)-56,900\left( 1-0.081\right)\times 0.081\\\Rightarrow 56,900\left( 1-0.081\right)\cdot \left( 1-0.081\right)\\\Rightarrow 56,900\left( 1-0.081\right)^2$

After $x$ years it is

$\Rightarrow 56,900\left( 1-0.081\right)^x$

$\Rightarrow 56,900\left( 0.919\right)^x$

5 0

2 years ago

I BET YOU CANT SOLVE THIS...

e-lub [12.9K]

The answer is 61 7/20

8 0

3 years ago

A frequency distribution for the class level of students in an introductory statistics course is shown. Two students are randoml

Andrews [41]

Answer: $\dfrac{21}{410}$ .

Step-by-step explanation:

Formula : Probability = $\dfrac{\text{favorable outcomes}}{\text{Total outcomes}}$

From the given frequency distribution for the class level of students in an introductory statistics course, we have

Number of Junior= 12

Number of Senior = 7

Total students = 6+16+12+7 = 41

Probability that the first student obtained is a junior = $\dfrac{12}{41}$

Probability that the the second student obtained is a senior. $=\dfrac{7}{41-1}=\dfrac{7}{40}$

Then, the probability that the first student obtained is a junior and the second a senior would be $\dfrac{12}{41}\times\dfrac{7}{40}=\dfrac{21}{410}$

Hence, the required probability is $\dfrac{21}{410}$ .

8 0

3 years ago

PLEASE HELP Simplify (a^6)*(a^8)*(a^n)

Varvara68 [4.7K]

Answer:

$a^{14+n}$

Step-by-step explanation:

You add the exponents when the number/variable is the same, so:

6+8+n= 14+n

So:

$a^{14+n}$

4 0

3 years ago