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EastWind [94]
3 years ago
5

Due today :(((((((((((((((

Mathematics
2 answers:
Sedbober [7]3 years ago
7 0
I think it is D. (If it’s multiple choice then let me know.)
SVETLANKA909090 [29]3 years ago
3 0

Answer:

E(last one)

Step-by-step explanation:

We dont know much for this, so lets just go over the basics of what we know:

Most of the numbers are between 2-7.

Very very few of the numbers are 9<

Now there is the number 8, which is not spoken of, so we can just conclude that it doesnt matter how many we see in a list of numbers.

Now, looking at each, we should be able to figure out which one is correct by which set of numbers has the lowest amount of numbers between 9<.

In the first case, 3 of the numbers are 9<(9, 9, and 11)

In the second case, 7 of the numbers are 9<(14, 11, 12, 9, 10, 9, 11)

In the third case, 3 of the numbers are 9<(14, 9, 11)

In the fourth case, 5 of the numbers are 9<(12, 14, 10, 11, 11)

Finally, in the fifth case, 2 of the numbers are 9<(9, 10)

So it must be the fifth answer, since it has the least with numbers 9<.

Hope this helps!

Love your profile picture by the way :D

Note that if it is multiply choice, the first, second, and fifth answer would work.

If it is single choice, then it will definatly be the fifth answer.

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Given polynomials p, q, r, and s . q≠0 ,s≠0 and r≠0
kkurt [141]

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\frac{p}{q} \div \frac{r}{s} = \frac{ps}{qr}

Step-by-step explanation:

Given

\frac{p}{q} \div \frac{r}{s} =

Required

Solve

\frac{p}{q} \div \frac{r}{s} =

Turn division to multiplication

\frac{p}{q} \div \frac{r}{s} = \frac{p}{q} * \frac{s}{r}

\frac{p}{q} \div \frac{r}{s} = \frac{ps}{qr}

8 0
3 years ago
Find the distance from the point (4,2) to the point (0,1).
vagabundo [1.1K]

Answer:

4.123 units

Step-by-step explanation:

Data provided:

Coordinates of point 1 as ( 4 , 2)

and,

Coordinates of point 2 as ( 0 , 1 )

Now,

The distance between the two point whose coordinates are given is calculated using the formula as:

distance = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

on substituting the values, we get

distance = \sqrt{(0-4)^2+(1-2)^2}

or

distance = \sqrt{(-4)^2+(-1)^2}

or

distance = \sqrt{16+1}

or

Distance = √17 = 4.123 units

6 0
3 years ago
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