<em>My goodness, this is rather confusing in the way it is worded. Nevertheless, I will attempt to do what I can. Just please keep in mind that this is my own interpretation of the problem, and therefore could be... incorrect.</em>
<em>I think, to start out, we could set up the problem like so</em>
<em>15 + t ≥ 26</em>
<em>because t is not a set number. </em>
<em>Then all that is needed is to subtract 15 from both sides, and the equation becomes</em>
<em>t ≥ 11</em>
<em>So the resulting answer is t ≥ 11.</em>
<em />
<em>I hope that my interpretation helps.</em>
<em>-Toremi</em>
<em />
Answer:
<h2>b = 15°</h2>
Step-by-step explanation:
If Pq = RQ then ΔPQR is the isosceles triangle. The angles QPR and PRQ have the same measures.
We know: The sum of the measures of the angeles in the triangle is equal 180°. Therefore we have the equation:
m∠QPR + m∠PRQ + m∠RQP = 180°
We have
m∠QPR = m∠PRQ and m∠RQP = 60°
Therefore
2(m∠QPR) + 60° = 180° <em>subtract 60° from both sides</em>
2(m∠QPR) = 120° <em>divide both sides by 2</em>
m∠QPR = 60° and m∠PRQ = 60°
Therefore ΔPRQ is equaliteral.
ΔPSR is isosceles. Therefore ∠SPR and ∠PRS are congruent. Therefore
m∠SPR = m∠PRS
In ΔAPS we have:
m∠SPR + m∠PRS + m∠RSP = 180°
2(m∠SPR) + 90° = 180° <em>subtract 90° from both sides</em>
2(m∠SPR) = 90° <em>divide both sides by 2</em>
m∠SPR = 45° and m∠PRS = 45°
m∠PRQ = m∠PRS + b
Susbtitute:
60° = 45° + b <em>subtract 45° from both sides</em>
15° = b
Answer:
0
Step-by-step explanation:
since the "b" in y=mx+b ends up being 0, that means that the y intercept is 0, which also means that the x intercept is 0.
<span>△PQR is similar to △STU
</span>m∠R = m∠U = 96°
m∠Q = m∠T = 6
m∠P = 180 - ( 96 + 6)
m∠P = 180 - 102
m∠P = 78
answer
m∠P = 78
Area of square = 2^2 = 4
area of trapezoid = 1/2(4+7)(6) = 1/2(11)(6) = 33
area of figure = 33 - 4 = 29
answer
29 cm^2
