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3 years ago

The question is in the picture pls help <3

Mathematics

2 answers:

QveST [7]3 years ago

4 0

Answer:

Step-by-step explanation:

ioda3 years ago

4 0

Answer:

the answer is B

Step-by-step explanation:

Since you have 2 negative numbers present in the problem that can only mean addition since they are both negative, and option B clearly states that. Hoped this helped :)

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This makes no sense, math, i need help because this is BS and i don’t get it. there must be something i am missing.

nevsk [136]

Answer:

You are correct! But note the syntax:

the computer wants you to type in the box

2/3 x - 2

because "y =" is already written!

Step-by-step explanation:

4 0

3 years ago

Quadrilateral ABCD is inscribed. The measure of ZA = 67º. What is the measure of ZC?

Luda [366]

Answer:

m<C = 113°

Step-by-step explanation:

m<A = 67° (given)

Recall: opposite angles in any inscribed quadrilateral in a circle are equal to 180° or are supplements of one another.

This implies that:

m<A + m<C = 180°

Substitute

67° + m<C = 180°

Subtract 67° from each side

m<C = 180° - 67°

m<C = 113°

7 0

3 years ago

888,000,000 (0.0000018) over 0.00004 use scientific notation to calculate....???

NeTakaya

(4xx10^-5 0.00004<span> =4/100000 =4/10^5 =color(blue)(4xx10^-5.

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6 0

3 years ago

Find the value of the variable y, for which:

schepotkina [342]

The value of the variable y is $y=6$

Explanation:

The given equation is $\frac{6}{y-4}-\frac{y}{y+2}=\left(\frac{6}{y-4}\right)\left(\frac{y}{y+2}\right)$

Taking LCM on LHS of the equation, we get,

$\frac{6(y+2)-y(y-4)}{(y-4)(y+2)}=\left(\frac{6}{y-4}\right)\left(\frac{y}{y+2}\right)$

Simplifying the term on RHS of the equation, we get,

$\frac{6(y+2)-y(y-4)}{(y-4)(y+2)}=\frac{6 y}{(y-4)(y+2)}$

Since, both the sides of the equation have the same denominator, we can cancel them.

Thus, we have,

$6(y+2)-y(y-4)=6 y$

Multiplying the terms within the bracket, we get,

$6y+12-y^2-4y=6 y$

Adding the like terms, we have,

$2y+12-y^2=6 y$

Subtracting both sides by $6 y$ , we have,

$-4y+12-y^2=0$

Factoring the equation, we get,

$(y+2)(y-6)=0$

$y=-2, y=6$

The values of the variable y are $y=-2, y=6$

At the point $y=-2$ , the equation $\frac{6}{y-4}-\frac{y}{y+2}=\left(\frac{6}{y-4}\right)\left(\frac{y}{y+2}\right)$ becomes undefined.

Thus, the value of the variable y is $y=6$

8 0

4 years ago

I need somebody to help me find the answer because this stuff makes no sense to me but my teacher don’t know that soo

kotykmax [81]

Answer:

Math notes

Step-by-step explanation:

Here are some of my notes from my class but you can use them to answer your questions and if you need help with a question just tell me!!

It looks like I help to put the link in the chat because it doesn't let my submit it.

Hopes this helps!!

3 0

3 years ago