The answer to this question is B) 44.78
Solution :
= 178 x 0.48
= 85.44
≈ 85
= 427 x 0.38
= 162.26
≈ 162
a). Yes, the sample sizes are large enough to use the large sample confidence interval so as to estimate the difference in the population proportions.
Let 
Where the 
the age 
group and the 2 - subscript indicates the age 
group.
Since 
are all at least 10, the sample sizes are large enough to use the large sample confidence interval.
= 0.409421
= 1 - 0.4094
= 0.5906
b). 90% confidence interval is
c). Zero is not included in the confidence interval. Answer is no. The difference in the two population proportion are different from each other.
Answer:
Step-by-step explanation:
Given:
E is the midpoint of segment AC.
AE ≅ EC
∠BAE ≅ ∠ECD
To prove:
ΔAEB ≅ ΔCED
Statements Reasons
1). AE ≅ EC 1). Given
2). ∠BAE ≅ ∠ECD 2). Given
3). ∠AEB ≅ ∠CED 3). Vertically opposite angles theorem
4). ΔAEB ≅ ΔCED 4). By ASA postulate of congruence
The numbers are "x" and "y", therefore, we suggest this system of equations:
x-y=14
xy=1800
We can solve by substitution method.
x=14+y
(14+y)y=1800
14y+y²=1800
y²+14y-1800=0
Now, we solve this square equation:
y=[-14⁺₋√(196+7200)] / 2=(-14⁺₋86)/2
We have two solutions:
y₁=(-14-86)/2=-50 ⇒x=14+y=14-50=-36
y₂=(-14+86)/2=36 ⇒x=14+y=14+36=50
Answer: we have two solutions:
Solution1: The first number is -36 and the other number is -50
Soltuion2: The first number is 50 and the other number is 36
Area of this rectangle
4×3=12cm^2
formula
long side×short side=area of this rectangle
