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ikadub [295]
3 years ago
9

One month kris rented 3 movies and 8 video games for a total of $53. the next month she rented 5 movies and 2 video games for a

total of $26. find the rental cost
Mathematics
1 answer:
SCORPION-xisa [38]3 years ago
6 0
Make a system of equations and solve for each variable.

3m+8v=53
5m+2v=26

m= movie cost
v= game cost

multiply the bottom equation by 4(combination method)

3m+8v=53
20m+8v=104. Subtract

-17m = -51
m= 3

Plug back into one of the equations

5(3)+2v=26
15+2v=26
2v=11
v=5.5

m=$3
v=$5.5


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Step-by-step explanation:

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3 years ago
Need help with this math question
olga_2 [115]

The correlation coefficient is -0.87; strong correlation

<h3>How to determine the correlation coefficient?</h3>

The given parameters are:

x = Time spent working out

y = lbs Overweight

Next, we enter the table of values in a graphing tool.

From the graphing tool, we have the following summary:

<u>X Values</u>

  • ∑ = 27.1
  • Mean = 2.71
  • ∑(X - Mx)2 = SSx = 22.569

<u>Y Values</u>

  • ∑ = 89
  • Mean = 8.9
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<u>X and Y Combined</u>

  • N = 10
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<u>R Calculation</u>

r = ∑((X - My)(Y - Mx)) / √((SSx)(SSy))

r = -114.19 / √((22.569)(778.9))

r = -0.8613

Approximate

r = -0.87

This means that the correlation coefficient is -0.87

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2 years ago
What is the solution to the equation 3 over 1⁄2 plus P. equals 5 over 1⁄4​
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8 0
2 years ago
A colony of bacteria is growing at a rate of 0.2 times its mass. Here time is measured in hours and mass in grams. The mass of t
11Alexandr11 [23.1K]

Answer:

  • <u>Question 1:</u>      dm/dt=0.2m<u />

<u />

  • <u>Question 2:</u>     m=Ae^{(0.2t)}<u />

<u />

  • <u>Question 3:</u>      m=10e^{(0.2t)}<u />

<u />

  • <u>Question 4:</u>      m=10g<u />

Explanation:

<u>Question 1: Write down the differential equation the mass of the bacteria, m, satisfies: m′= .2m</u>

<u></u>

a) By definition:  m'=dm/dt

b)  Given:  rate=0.2m

c) By substitution:  dm/dt=0.2m

<u>Question 2: Find the general solution of this equation. Use A as a constant of integration.</u>

a) <u>Separate variables</u>

     dm/m=0.2dt

b)<u> Integrate</u>

           \int dm/m=\int 0.2dt

            ln(m)=0.2t+C

c) <u>Antilogarithm</u>

       m=e^{0.2t+C}

       m=e^{0.2t}\cdot e^C

         e^C=A\\\\m=Ae^{(0.2t)}

<u>Question 3. Which particular solution matches the additional information?</u>

<u></u>

Use the measured rate of 4 grams per hour after 3 hours

            t=3hours,dm/dt=4g/h

First, find the mass at t = 3 hours

            dm/dt=0.2m\\\\4=0.2m\\\\m=4/0.2\\\\m=20g

Now substitute in the general solution of the differential equation, to find A:

          m=Ae^{(0.2t)}\\\\20=Ae^{(0.2\times 3)}\\\\A=20/e^{(0.6)}\\\\A=10.976

Round A to 1 significant figure:

  • A = 10.

<u>Particular solution:</u>

           

             m=10e^{(0.2t)}

<u>Question 4. What was the mass of the bacteria at time =0?</u>

Substitute t = 0 in the equation of the particular solution:

         m=10e^{0}\\\\m=10g

3 0
3 years ago
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