PLEASEEEEEE HELP!!

At a basketball game, the manager of the arena wanted to know how many fans from the away team were in attendance. He noticed th

Stells [14]

Answer:

About 150 people.

Step-by-step explanation:

1.) 15/36 = x/360

2.) 150/360 = x/360

3.) 150/360 = 150/360

6 0

3 years ago

What are “like terms”? Why can we only add like terms?

SSSSS [86.1K]

Answer:

Like terms are terms whose variables are the same.

We can only add them because if they does not have the same variable you do not actually know if the variables are equivalent and you will get the wrong answer.

Step-by-step explanation:

Ex: 4z,7z,108z,45z

Ex: 4w-2h+7a-2w

You can not add 4w and 7a because you do not know what the variables equal so you do not know the true number so add or subtract by.

4 0

2 years ago

Find the equation of the lien shown.

Mnenie [13.5K]

Answer:

y = $\frac{1}{2}$ x

Step-by-step explanation:

the equation of a line passing through the origin is

y = mx ( m is the slope )

calculate m using the slope formula

m = $\frac{y_{2}-y_{1} }{x_{2}-x_{1} }$

with (x₁, y₁ ) = (0, 0) and (x₂, y₂ ) = (6, 3) ← 2 points on the line

m = $\frac{3-0}{6-0}$ = $\frac{3}{6}$ = $\frac{1}{2}$

y = $\frac{1}{2}$ x ← equation of line

7 0

1 year ago

This is a picture of a cube and the net for the cube.

Nataliya [291]

Answer:

1196 mm^2

Step-by-step explanation:

That's really well described. All in all you have 6 squares all laid out flat. Each square has a side of 14 mm.

The area of 1 square = 14mm * 14mm = 196 mm^2

The area of 6 squares = 6 * 196 mm^2 = 1176 mm^2

3 0

3 years ago

A restaurant chain has two locations in a medium-sized town and, believing that it has oversaturated the market for its food, is

scoray [572]

Answer:

Yes, since the test statistic value is greater than the critical value.

Step-by-step explanation:

Data given and notation

$\bar X_{1}=360000$ represent the mean for the downtown restaurant

$\bar X_{2}=340000$ represent the mean for the freeway restaurant

$s_{1}=50000$ represent the sample standard deviation for downtown

$s_{2}=40000$ represent the sample standard deviation for the freeway

$n_{1}=36$ sample size for the downtown restaurant

$n_{2}=36$ sample size for the freeway restaurant

t would represent the statistic (variable of interest)

$\alpha=0.05$ significance level provided

Develop the null and alternative hypotheses for this study?

We need to conduct a hypothesis in order to check if the true mean of revenue for downtown is higher than for freeway restaurant, the system of hypothesis would be:

Null hypothesis: $\mu_{1}\leq \mu_{2}$

Alternative hypothesis: $\mu_{1} > \mu_{2}$

Since we don't know the population deviations for each group, for this case is better apply a t test to compare means, and the statistic is given by:

$t=\frac{\bar X_{1}-\bar X_{2}}{\sqrt{\frac{s^2_{1}}{n_{1}}+\frac{s^2_{2}}{n_{2}}}}$ (1)

t-test: Is used to compare group means. Is one of the most common tests and is used to determine whether the means of two groups are equal to each other.

Determine the critical value.

Based on the significance level $\alpha=0.05$ and $\alpha/2=0.025$ we can find the critical values from the t distribution dith degrees of freedom df=36+36-2=55+88-2=70, we are looking for values that accumulates 0.025 of the area on the right tail on the t distribution.

For this case the value is $t_{1-\alpha/2}=1.66$

Calculate the value of the test statistic for this hypothesis testing.

Since we have all the values we can replace in formula (1) like this:

$t=\frac{360000-340000}{\sqrt{\frac{50000^2}{36}+\frac{40000^2}{36}}}}=1.874$

What is the p-value for this hypothesis test?

Since is a right tailed test the p value would be:

$p_v =P(t_{70}>1.874)=0.033$

Based on the p-value, what is your conclusion?

Comparing the p value with the significance level given $\alpha=0.05$ we see that $p_v$ so we can conclude that we reject the null hypothesis, and the true mean for the downtown revenue restaurant seems higher than the true mean revenue for the freeway restaurant.

The best option would be:

Yes, since the test statistic value is greater than the critical value.

5 0

2 years ago