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DIA [1.3K]
3 years ago
15

PLEASEEEEEE HELP!!

Mathematics
1 answer:
elena-s [515]3 years ago
3 0

Answer:

ya 5x is the right anwser

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Shelly is 3 years older than Michelle. 4 years ago the sum of their ages was 67. find the age of each person now
Murljashka [212]
If Shelly is 3 years older than Michael and There 67. Michael is 64 and Shelly is 67. Or Michael is 67 and Shelly is 70.

Hope I helped. Have a wonderful day
3 0
3 years ago
Mackenzie practices the piano 609 minutes in 3 weeks. At what rate did she practice, in minutes per day?​
Step2247 [10]

Answer:

the answer is 29

Step-by-step explanation:

good luck! <33

6 0
3 years ago
Read 2 more answers
= 21229<br> = 72112<br> = 18284<br> ⚫️ = ?
lidiya [134]
do you mean by this
6 0
3 years ago
You are competing in a race. The table shows the times from last year's race. You want your time to be last year's median time w
olasank [31]

Answer:

  28 ≤  x ≤40

Step-by-step explanation:

Arrange the data from the smallest to the largest

26, 27, 28,32, 32, 33, 35, 36, 38, 40,42,48

Identify the median value

26, 27, 28,32, 32,<u> 33, 35</u>, 36, 38, 40,42,48

Getting the median

(33+35)/2   =  68/2  = 34 minutes

You want your time to be last year's median time with an absolute deviation of at most 6 minutes

This mean ±6 minutes, hence this will be 34 ± 6

34+6=40  and 34-6=28

The inequality will be    28 ≤  x ≤40

7 0
3 years ago
Read 2 more answers
Help plzzzz! pre calc question
Mumz [18]

Answer:

\sum^{\infty}_0 {(-3)^n}

Step-by-step explanation:

Notice that the series: 1 - 3 + 9 - 27 +... clearly has powers of the factor 3 in its terms and it is also an alternate series (the terms alternate from positive to negative). The terms are positive for a_0, a_2, a_4, ... (even terms) , while the odd terms a_1, a_3, a_5, ... are negative. (so most likely there should be a factor   (-1) in the common ratio.

We can then represent it with the following summation expression:

\sum^{\infty}_0 {(-3)^n} given that each of its first four terms are:

a_0=(-3)^0=1\\a_1=(-3)^1=-3\\a_2=(-3)^2=(-3)*(-3)=9\\a_3=(-3)^3=(-3)*(-3)*(-3)=-27

7 0
3 years ago
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