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77julia77 [94]
3 years ago
7

Simplify. 2x + 6x2 10 + 4x2 – 3x + (-6) =

Mathematics
2 answers:
Anika [276]3 years ago
6 0

Answer: 14x,4+4x ^2-3x

 

Step-by-step explanation:

1. Simplify  6x\times 26x×2  to  12x12x.

2x+12x,10+4{x}^{2}-3x-6

2x+12x,10+4x  

2

−3x−6

2 Simplify  2x+12x2x+12x  to  14x14x.

14x,10+4{x}^{2}-3x-6

14x,10+4x  

2

−3x−6

3 Collect like terms.

14x,((10-6)+4{x}^{2}-3x)

14x,((10−6)+4x  

2

−3x)

4 Simplify  (10-6)+4{x}^{2}-3x(10−6)+4x  

2

−3x  to  4+4{x}^{2}-3x4+4x  

2

−3x) Hope that helps

Blizzard [7]3 years ago
4 0
God bless you ma’am/sir!!
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The ground temperature at an airport is 10 °C. The temperature decreases by 5.4 °C for every increase of 1 kilometer above the g
Paraphin [41]

The temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Given that,

  • The ground temperature at the airport is 10 °C.
  • The decrease in temperature is 5.4°C for each & every rise in 1 kilometer.

Based on the above information, the temperature outside should be

The decrease in the temperature should be

= 5.4×5

= 27°C

Now the final temperature is

= 10 - 27

= -17°C

Therefore we can conclude that the temperature outside a plane flying at an altitude of 5 kilometers is -17°C.

Learn more: brainly.com/question/20459283

5 0
2 years ago
Ill give you Brainlyest! I need help ASAP work shown, please!!<br> problems 8-15
8_murik_8 [283]

Using the segment addition theorem, the solutions are:

5. x = 17

6. x = 7

7. x = 14

BC = 27

CD = 61

BD = 88

8. AB = 26

9. LJ = 46

10. x = 3

11. FG = 15

12. QS = 34

13. BC = 26

14. EG = 19

15. QS = 68

<h3>How to Apply the Segment Addition Theorem?</h3>

The segment addition theorem would be used to solve the problems as shown below:

5. UW = UV + VW [segment addition theorem]

Substitute

6x - 35 = 19 + 4x - 20

6x - 4x = 35 + 19 - 20

2x = 34

x = 17

6. HJ = HI + IJ [segment addition theorem]

Substitute

7x - 27 = 3x - 5 + x - 1

7x - 3x - x = 27 - 5 - 1

3x = 21

x = 7

7. BD = BC + CD [segment addition theorem]

Substitute

7x - 10 = 4x - 29 + 5x - 9

7x - 4x - 5x = 10 - 29 - 9

-2x = -28

x = 14

BC = 4x - 29 = 4(14) - 29 = 27

CD = 5x - 9 = 5(14) - 9 = 61

BD = 7x - 10 = 7(14) - 10 = 88

8. BC = BD

Substitute

2x + 1 = 5x - 26

2x - 5x = -1 - 26

-3x = -27

x = 9

AB = 43 - BC

AB = 43 - 2x + 1 = 43 - 2(9) + 1 = 26

9. 7x - 10 = 9x - 11 - (x + 3)

7x - 10 = 9x - 11 - x - 3

7x - 9x + x = 10 - 11 - 3

-x = -4

x = 4

LJ = 28 + 7x - 10 = 28 + 7(4) - 10

LJ = 46

10. 8x + 11 = 12x - 1

8x - 12x = -11 - 1

-4x = -12

x = 3

11. 11x - 7 = 3x + 9

11x - 3x = 7 + 9

8x = 16

x = 2

FG = 11x - 7 = 11(2) - 7

FG = 15

12. 5x - 3 = 21 - x

5x + x = 21 + 3

6x = 24

x = 4

QS = 2(5x - 3) = 10x - 6 = 10(4) - 6

QS = 34

13. 8x - 20 = 2(3x - 1)

8x - 20 = 6x - 2

8x - 6x = 20 - 2

2x = 18

x = 9

BC = AB = 3x - 1 = 3(9) - 1

BC = 26

14. 5x - 1 = 7x - 13

5x - 7x = 1 - 13

-2x = -12

x = 6

EG = 6x - 4 - 13 = 6(6) - 4 - 13

EG = 19

15. RT - ST = RS

Substitute

8x - 43 - (4x - 1) = 2x - 4

8x - 43 - 4x + 1 = 2x - 4

4x - 42 = 2x - 4

4x - 2x = 42 - 4

2x = 38

x = 19

QS = 2(RS)

QS = 2(2x - 4) = 4x - 8 = 4(19) - 8

QS = 68

Learn more about the segment addition theorem on:

brainly.com/question/28263183

#SPJ1

8 0
2 years ago
Solve for qqq.
Anna11 [10]
3/5=q/10
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8 0
3 years ago
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What is the altitude of a rhombus if its area is 10 square meters and the length on one side is 2.5 meters?
Elan Coil [88]
10/2.5= 4 the answer is 4 meters because you just divide them. 

4 0
3 years ago
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"400 reduced by 4 times my age is 116." what is his age?
Lynna [10]
400 reduced by 4 times my age is 116...

400 - 4x = 116
-4x = 116 - 400
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x = -284/-4
x = 71 <===
4 0
3 years ago
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