Answer:

Step-by-step explanation:
Given



Orchestral =
of music practice time
Required
Determine time spent on orchestral pieces
From the given parameters, we have:
Orchestral =
of music practice time
Substitute
for music practice time.
So, we have:



Answer:
The 95% confidence interval is (29.54 - 53.46}
Step-by-step explanation:
given data:

Se = 6.1
n = 755
a) best estimate 
b) at 95% confidence interval



at 95% confidence interval for [/tex]\mu[/tex]



The 95% confidence interval is (29.54 - 53.46}
If x - 4 ≥ 0, then |x - 4| = x - 4, so
G(x) = F(x) ⇒ 3x + 2 = (x - 4) + 2
⇒ 3x + 2 = x - 2
⇒ 2x = -4
⇒ x = -2
Otherwise, if x - 4 < 0, then |x - 4| = -(x - 4), so
G(x) = F(x) ⇒ 3x + 2 = -(x - 4) + 2
⇒ 3x + 2 = -x + 6
⇒ 4x = 4
⇒ x = 1
However,
• when x = -2, we have
G(-2) = 3(-2) + 2 = -4
F(-2) = |-2 - 4| + 2 = 8
• when x = 1, we have
G(1) = 3(1) + 2 = 5
F(1) = |1 - 4| + 2 = 5
so only x = 1 is a solution to G(x) = F(x).
Answer:
8. 7.2
9. 6.7
Step-by-step explanation:
Answer:
3) 5.4
Step-by-step explanation:
Given two points (x1, f(x1)) and (x2, f(x2)), the average rate of change is computed as follows:
[f(x2) - f(x1)]/[x2 - x1]
From the original photograph to the fourth enlargement, the points are (0, 15) and (4, 36.6). Replacing into the equation we get:
[36.6 - 15]/[4 - 0] = 5.4