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daser333 [38]
3 years ago
15

Please solve for x. 43x+1 = 45

Mathematics
1 answer:
Jet001 [13]3 years ago
7 0

Answer:

x=44/43

Step-by-step explanation:

Subtract 1 from both sides

Simplify

Divide both sides by the same term

Cancel terms that are in both the numerator and the denominator

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F(x)= -3x^3-x^2+x-3 identify the end behavior of each polynomial function
sashaice [31]

end behavior is affect by the exponent and whether its negative or positive

y = y^3 starts negative from -∞ to 0 the from 0 to +∞ goes positive

since this equation is negative its switched

-∞ to 0  its positive x>0

0 to +∞ is negative x<0

3 0
3 years ago
What i 12% of 32? is 32the part or the whole???
Valentin [98]
32 is the whole 12.16 is 12 percent of 32
7 0
4 years ago
Item 8
ludmilkaskok [199]
So, I didn't quite understand your question clearly, but I'll try my best to answer it.

So, the first question is quite simple: Did the runner have a % decrease in his time or an increase.
Well, 7:45 is minor than 5:51. So, his time decreased.

2nd question:
The percent of change. Well, first things first 7:45 has 2 different units, wich are minutes and seconds, I suppose. Same goes for 5:51.
So let's put everything in seconds. multiply both the 7 and 5 for 60(for every minute has 60 seconds.)

That means:
7*60= 420+45 = 465.
5*60=300+51=351.

Now, let's do the math itself:
465 -> 100%
351 -> x%
 Is equal to about  75,5%
How much did it decrease then?
(75,5-100)%= 24,5%, approximately

8 0
3 years ago
Our environment is very sensitive to the amount of ozone in the upper atmosphere. The level of ozone normally found is 7.5 parts
Hunter-Best [27]

Answer:

The value of the test statistic is t = 2.1

Step-by-step explanation:

Our test statistic is:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

In which X is the sample mean, \mu is the expected value, \sigma is the standard deviation and n is the size of the sample.

The level of ozone normally found is 7.5 parts/million (ppm).

This means that \mu = 7.5

The mean of 24 samples is 7.8 ppm with a standard deviation of 0.7.

This means that X = 7.8, \sigma = 0.7, n = 24

Test Statistic:

t = \frac{X - \mu}{\frac{\sigma}{\sqrt{n}}}

t = \frac{7.8 - 7.5}{\frac{0.7}{\sqrt{24}}}

t = 2.1

The value of the test statistic is t = 2.1

7 0
3 years ago
Please answer ASAP! All help is deeply appreciated! Stay safe!
NNADVOKAT [17]

Answer:

C. 150

Step-by-step explanation:

60+150+120+270=600

600/4=150

5 0
3 years ago
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