A shipment of 20tvs contains 5 that are defective. if 10 of them are randomly chosen for inspection, what is the probability tha
t 2 out of 10 will be defective?
1 answer:
1/4 of the shipment is defective so if half is randomly chosen to test the answer would be 5/20 or 2/10 so 1/4 or 1/5
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2x and 7x is the answer of the questions
ANSWER: n = -16
4n + 13n = 17n
19 + 13 = 32
15 - 17 = -2
n = -16
The unit rate is $1.97 per lightbulb. Multiply $1.97 by 7 to get 13.79
Answer:
C).
Step-by-step explanation:
-3x+2 and[(-)(x^2+5x)
3x+2 and (-x^2+5x)
3x+2-x^2+5x
-x^2-8x+2
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