At the rate of 15 per 6 oz. bar of chocolate, how much would a pound

Mathematics

1 answer:

tankabanditka [31]3 years ago

5 0

Answer:

Step-by-step explanation:

We know there are 16 oz in a pound

We can use ratios

15 x

----- = ----------

6 oz 16 oz

Using cross products

15 * 16 = 6x

240 = 6x

divide by 6

240/6 = 6x/6

40 =x

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A tent for a family of 6 is on sale for $109.99. Find the volume of space inside the tent for the family to sleep.

mel-nik [20]

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4 0

3 years ago

HELp meh with this question it very hard

Dovator [93]

Answer:

AB = 7 cm

Step-by-step explanation:

Use the law of cosines to find the side AB:

$AB = \sqrt{(x + 3)^2+x^2-2x(x+3)cos (60)} =$
$\sqrt{x^2+6x+9+x^2-x^2-3x} = \sqrt{x^2+3x+9}$

Use the Heron's area formula next:

$A = \sqrt{s(s - a)(s-b)(s-c)}$ , where s- semi perimeter

s = 1/2[x + x + 3 + $\sqrt{x^2+3x+9}$ ) = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ )
s - a = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ - 2x - 6) = 1/2 ( $\sqrt{x^2+3x+9 }$ - 3)
s - b = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ - 2x) = 1/2 ( $\sqrt{x^2+3x+9}$ + 3)
s - c = 1/2 (2x + 3 + $\sqrt{x^2+3x+9}$ - 2 $\sqrt{x^2+3x+9}$ ) = 1/2 (2x + 3 - $\sqrt{x^2+3x+9}$ )