Can someone please help me with this question for hw

Fifteen hungry kittens found a bucket of sausages. Each time

raketka [301]

Answer:

2.4 SAUSAGES

Step-by-step explanation:

18 x 2 = 36

36/ 15 = 2.4

6 0

1 year ago

4) From a graphed linear line, how do you find the Slope: Y-intercept:

Ad libitum [116K]

Rise over Run

Put the amount you go up or down on the Y-axis over how much you go right or the x-axis

the Y-intercept is found simply by looking where the graph crosses the y, if the equation is written instead of graphed, graph it using a graphing calculator, then use the information I gave you previously : )

8 0

2 years ago

Which expressions are equivalent to − f − 5 ( 2 f − 3)

Drupady [299]

Answer:

I need the expressions

Step-by-step explanation:

(I don't have the experresions but I think it might be helpful to simplify)

- f - 5 ( 2 f - 3)

−f−10f+15

−f−(10f−15)

(−f−10f)+15

−11f+15 

Hope this helped

3 0

2 years ago

Find the slope of the graph of the equation

sammy [17]

Answer:

y=-1/2x+2

Step-by-step explanation:

slope is -1/2 beware this is a negitive slope so it goes down like this \

go one up and go to the left 2 times and connect the dots

6 0

2 years ago

] It is claimed that 42% of US college graduates had a mentor in college. For a sample of college graduates in Colorado, it was

Bad White [126]

Answer:

$z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930$

The p value for this case would be given by:

$p_v =P(z>3.930)=0.0000443$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

Step-by-step explanation:

Information given

n=1045 represent the random sample selected

X=502 represent the college graduates with a mentor

$\hat p=\frac{502}{1045}=0.480$ estimated proportion of college graduates with a mentor

$p_o=0.42$ is the value that we want to test

z would represent the statistic

$p_v$ represent the p value

Hypothesis to test

We want to test if the true proportion is higher than 0.42, the system of hypothesis are.:

Null hypothesis: $p \leq 0.42$

Alternative hypothesis: $p > 0.42$

The statistic is given by:

$z=\frac{\hat p -p_o}{\sqrt{\frac{p_o (1-p_o)}{n}}}$ (1)

Replacing the info we got:

$z=\frac{0.480 -0.42}{\sqrt{\frac{0.42(1-0.42)}{1045}}}=3.930$

The p value for this case would be given by:

$p_v =P(z>3.930)=0.0000443$

For this case the p value is lower than the significance level so then we have enough evidence to reject the null hypothesis so then we can conclude that the true proportion is significantly higher than 0.42

7 0

2 years ago