Hello!
First of all let's find the perimeter (circumference) of the semi circles. We can combine them to make one circle with a diameter of 4 (as we can see the side length of one semi circle is 4 cm. We now plug it into the circumference equation (

=3.14).
4(3.14)=12.56
Now we add up the side lengths of the rectangle.
4+6+4+6=20
Now we add up the length of our circle and rectangle.
20+12.56=32.56
Therefore our answer is
32.56 cm.
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Now to find the area! If we combine the two semicircles, we get a circle with a diameter of four. This means that is has a radius of two. We use the equation below to find the area of the two circles.
A=

r²
First we will square our radius.
2(2)=4
Now we multiply by pi.
4(3.14)=12.56
Now we need to find the area of the rectangle.
6(4)=24
Now we add.
24+12.56=
36.56.
I hope this helps!
Hello,
I don't know the divison method but is it these one?
156.25= 625/4=(25/2)²
√156.25= 12.5
If Michael is pitched 20 balls he will at least hit ten of them!
It means that when both sides of an equation have the same number subtracted from them the remaining expressions are equal. ( ......Hope that I helped you...... )
Make a proportion to find Mr. Yoshi's percentage:
60/75 = x/100
Cross Products:
6000 = 75x
x = 80
So 60/75 = 80/100 which is 80%
Now for the student teacher:
The student teacher graded 75-60 = 15 papers.
Make a proportion:
15/75 = x/100
Cross products:
75x = 1500
x = 20
So 15/75 = 20/100 which is 20%
So Mr. Yoshi: 80%
Student Teacher: 20%
You can check by adding the two scores together and seeing if the sum is 100%:
80% + 20% = 100%
It is, so the answer is correct.