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2 years ago

My question is the picture

Mathematics

1 answer:

AysviL [449]2 years ago

5 0

Answer:

20 students

Step-by-step explanation:

You first have to add the number of students all up and you get 200.Then you do cross multiplication.

40/200 x s/100=

40x100= 4000=

200xs= 200s=

200s/200=

4000/200=

20=

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The radius of a cone is decreasing at a constant rate of 7 inches per second, and the volume is decreasing at a rate of 948 cubi

inessss [21]

Answer:

The height of cone is decreasing at a rate of 0.085131 inch per second.

Step-by-step explanation:

We are given the following information in the question:

The radius of a cone is decreasing at a constant rate.

$\displaystyle\frac{dr}{dt} = -7\text{ inch per second}$

The volume is decreasing at a constant rate.

$\displaystyle\frac{dV}{dt} = -948\text{ cubic inch per second}$

Instant radius = 99 inch

Instant Volume = 525 cubic inches

We have to find the rate of change of height with respect to time.

Volume of cone =

$V = \displaystyle\frac{1}{3}\pi r^2 h$

Instant volume =

$525 = \displaystyle\frac{1}{3}\pi r^2h = \frac{1}{3}\pi (99)^2h\\\\\text{Instant heigth} = h = \frac{525\times 3}{\pi(99)^2}$

Differentiating with respect to t,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)$

Putting all the values, we get,

$\displaystyle\frac{dV}{dt} = \frac{1}{3}\pi \bigg(2r\frac{dr}{dt}h + r^2\frac{dh}{dt}\bigg)\\\\-948 = \frac{1}{3}\pi\bigg(2(99)(-7)(\frac{525\times 3}{\pi(99)^2}) + (99)(99)\frac{dh}{dt}\bigg)\\\\\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi} = (99)^2\frac{dh}{dt}\\\\\frac{1}{(99)^2}\bigg(\frac{-948\times 3}{\pi} + \frac{2\times 7\times 525\times 3}{99\times \pi}\bigg) = \frac{dh}{dt}\\\\\frac{dh}{dt} = -0.085131$

Thus, the height of cone is decreasing at a rate of 0.085131 inch per second.

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2 years ago

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3 years ago

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Answer:

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Step-by-step explanation:

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2 years ago

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ASHA 777 [7]

Answer: " b = 3 ⅕ ; or, write as: 3.2 .
_____________________________________
Given: "A = (1/2) * b * h " ;

↔ A = (b * h) / 2

2A = (b*h) ;

2A/ h = b ;

↔ b = (2A) / h ;

Given A = 48 ; and h = 30 ; Plug in these values; and solve for "b" ;

→ b = (2*48) / 30 ;

= 96/30 ;

= (96÷6) / (30÷6) ;

→ b = 16/5 ; = 3 <span>⅕ ; or, write as: 3.2 .
_______________________________</span>

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2 years ago

My question is the picture​

My question is the picture