To draw the equation of a circle, you need the center coordinates
and the radius
.
Once you know them, you can write the equation for the circle as

We can eyeball the center coordinates: from the origin, we have to go one step right and two steps below, so the coordinates are 
For the radius, you can see that if you move three units up, down, left or right from the center, you reach the circumference. So, the radius is 3.
Given everything we said above, we're ready to write the equation:

Answer:
1998= 30,000 students
Step-by-step explanation:
Giving the following information:
In 1999, the student enrolment at a college was 13% more than it was in 1998. If the enrolment was 36,612 in 2000, which was 8% more than 1999, find the enrolment in 1998
<u>First, we need to determine the enrolment in 1999:</u>
1999= 36,612/1.08
1999= 33,900
<u>Now, we can find the enrolment in 1998:</u>
1998= 33,900/1.13
1998= 30,000
Answer:
D. The work shown above is correct, and
may not be simplified further.
Step-by-step explanation:
![\sqrt[4]{y^{23} } = \sqrt[4]{y^4 . y^4 . y^4.y^4.y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20%5Csqrt%5B4%5D%7By%5E4%20.%20y%5E4%20.%20y%5E4.y%5E4.y%5E3%7D)
![\sqrt[4]{y^4. y^4.y^4. y^4.y^3} = y^5 . \sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E4.%20y%5E4.y%5E4.%20y%5E4.y%5E3%7D%20%3D%20y%5E5%20.%20%5Csqrt%5B4%5D%7By%5E3%7D)
When we simplify, we get
![\sqrt[4]{y^{23} } = y^5.\sqrt[4]{y^3}](https://tex.z-dn.net/?f=%5Csqrt%5B4%5D%7By%5E%7B23%7D%20%7D%20%3D%20y%5E5.%5Csqrt%5B4%5D%7By%5E3%7D)
The answer: D. The work shown above is correct, and
may not be simplified further.
Thank you.
By the definition of a rectangle, JML and KLM are right angles.
<h3>How to explain the information?</h3>
From the information given, JKLM is a rectangle based on the definition as the opposite sides are equal.
Also, JML and KLM will be 90° since they're right angles. The opposite sides of a rectangle are congruent and equal.
Learn more about rectangles on:
brainly.com/question/25292087
#SPJ1
Length (L): 4w + 1
width (w): w
Perimeter (P) = 2L + 2w
62 = 2(4w + 1) + 2(w)
62 = 8w + 2 + 2w
62 = 10w + 2
60 = 10w
6 = w
Length: L = 4w + 1 → 4(6) + 1 → 24 + 1 → 25
Answer: 6 meters x 25 meters