Answer:
-1 < c < 9
Step-by-step explanation:
-6<2c-4<14
Add 4 to all sides
-6+4<2c-4+4<14+4
-2<2c<18
Divide by 2
-2/2<2c/2<18/2
-1 < c < 9
Answer
school building, so the fourth side does not need Fencing. As shown below, one of the sides has length J.‘ (in meters}. Side along school building E (a) Find a function that gives the area A (I) of the playground {in square meters) in
terms or'x. 2 24(15): 320; - 2.x (b) What side length I gives the maximum area that the playground can have? Side length x : [1] meters (c) What is the maximum area that the playground can have? Maximum area: I: square meters
Step-by-step explanation:
Okay so i would do this with a logarithm.
5^(2x) = 28
take the log of both sides
log5^(2x) = log28 and because of this log rule: logA^n = nlogA
(2x)log5= log28
then divide by log5 on both sides
2x = log28 / log5
and divide by 2
x = (log28 / log5) /2
this can be found with a calculator:
x= about 1.03521...
round that to whatever the question says to
Since both took 5 1/2 yards then you would have to add 5 1/2 yards together to get 11 yards
