Incomplete question. However, here is a similar question attached.
Solve 3x^2 + 17x - 6 = 0.
Based on the work shown to the left, which of these values are possible solutions of the equation? Check all of the boxes that apply
A X=-6
B X=6
C X=-1/3
D X=1/3
E X=0
Answer:
A and D
Step-by-step explanation:
Note that such question requires using completing the square method of solving equations. By using the values X= -6 and X= 1/3 we arrive at a solution.
Answer:
x is equal to 2.5 and -4.5
Step-by-step explanation:
-4(x + 1)² - 3 = -51
-4(x² + 2x + 1) - 3 = -51
-4x² - 8x -3 - 3 = -51
-4x² - 8x - 6 = -51
-4x² - 8x = -45
-4(x^2 + 2x) = -45
-4(x^2 + 2x + 1) = -49
-4(x + 1)² = -49
(x + 1)² = 49/4
x + 1 = ± √(49/4)
x + 1 = ± 7/2
x = -1 ± 3.5
x = 2.5, -4.5
Answer:
X-intercepts are also called zeros, roots, solutions, or solution sets.
Answer: 0.1457
Step-by-step explanation:
Let p be the population proportion.
Given: The proportion of Americans who are afraid to fly is 0.10.
i.e. p= 0.10
Sample size : n= 1100
Sample proportion of Americans who are afraid to fly =
We assume that the population is normally distributed
Now, the probability that the sample proportion is more than 0.11:
![P(\hat{p}>0.11)=P(\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}}>\dfrac{0.11-0.10}{\sqrt{\dfrac{0.10(0.90)}{1100}}})\\\\=P(z>\dfrac{0.01}{0.0090453})\ \ \ [\because z=\dfrac{\hat{p}-p}{\sqrt{\dfrac{p(1-p)}{n}}} ]\\\\=P(z>1.1055)\\\\=1-P(z\leq1.055)\\\\=1-0.8543=0.1457\ \ \ [\text{using z-table}]](https://tex.z-dn.net/?f=P%28%5Chat%7Bp%7D%3E0.11%29%3DP%28%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%3E%5Cdfrac%7B0.11-0.10%7D%7B%5Csqrt%7B%5Cdfrac%7B0.10%280.90%29%7D%7B1100%7D%7D%7D%29%5C%5C%5C%5C%3DP%28z%3E%5Cdfrac%7B0.01%7D%7B0.0090453%7D%29%5C%20%5C%20%5C%20%5B%5Cbecause%20z%3D%5Cdfrac%7B%5Chat%7Bp%7D-p%7D%7B%5Csqrt%7B%5Cdfrac%7Bp%281-p%29%7D%7Bn%7D%7D%7D%20%5D%5C%5C%5C%5C%3DP%28z%3E1.1055%29%5C%5C%5C%5C%3D1-P%28z%5Cleq1.055%29%5C%5C%5C%5C%3D1-0.8543%3D0.1457%5C%20%5C%20%5C%20%5B%5Ctext%7Busing%20z-table%7D%5D)
Hence, the probability that the sample proportion is more than 0.11 = 0.1457
