Answer:
There's a parking lot that is 600m² big. The lot must be able to hold at least 3 buses and 10 cars.
Each car takes up 6m² and each bus takes up 30m².
However, there can only be 60 vehicles in the lot at any given time.
The cost to park in the lot is $2.50 per day for cars and $7.50 per day for buses. The lot must make at least $75 each day to break even.
What is a possible car to bus ratio that would allow the lot to make profit?
There are 6 octects ( 8 bit numbers ) in a MAC address, so there's 256^6 possible addresses.
Answer:
Explanation:
(i) L1+L2 Error:
L1=[10,12,14]
L2=[20,22,24] # {n. 2 delete}
L1+L2
ans =
30 34 38
(ii) L1*2
ans =
20 24 28
(iii) L1
L1 =
10 12 14
that is incorrect! Playstation is the correct answer
