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4 years ago

Identify the function that is not exponential.

Mathematics

1 answer:

TiliK225 [7]4 years ago

4 0

$y=-2(0.1)^x-YES\\\\y=3(0.2)^x-YES\\\\y=5(0.4)^x-YES\\\\y=-2x^3-NOT\\\\\text{Answer:}\ y=-2x^3$

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Can I get some Help please

makkiz [27]

Answer:

f(-2) = 2

Step-by-step explanation:

The question is asking for the y-value of the point located at x = -2 on the graph. The point is at (-2, 2), so f(-2) = 2.

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3 years ago

Bill drove 200 miles in 4 hours. Justin drove 350 miles in 5 hours. If they each drove 560 miles, what is the total number of ho

Mazyrski [523]

Bill takes 11.2 hours and justin takes 8 hours

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3 years ago

A recent study reported that 22% of adults in France admitted to texting or e-mailing while driving. A random sample of 110 Fren

laila [671]

Answer:

Step-by-step explanation:

ported that 22% of adults in France admitted to texting or e-mailing while driving. A random sample of 110 French adults was randomly selected. What is the probability that 26

Using a binomial distribution with mean = n*p = 110*0.22 = 24.2 and variance = n*p*(1-p) = 24.2*(1-0.22) = 18.876

Approximating it to a normal distribution,

$P(x\geq 26)\\\\=P(Z\geq \frac{26-24.2}{\sqrt{18.876} } )\\\\=P(Z\geq 0.41)\\\\=0.3481$

3 0

3 years ago

F(x) = [[x]], what is f(0.9)?

andriy [413]

I believe the answer you're looking for is f(0.9) = 0.9

If you replace the first x with 0.9, you will be replacing any other x's in the problem with that value as well.

Since f(x) = x

f(0.9) = 0.9

4 0

4 years ago

The position function for a free-falling object is s(t) = -16t^2 + vt +5. A ball is thrown upward from the top of a 400-foot bui

mixer [17]

Answer:

6.21 seconds

Step-by-step explanation:

The position function of a free-falling object is,

$s(t) = -16t^2+v_0t+s_0$

Where,

$s_0$ = initial height of the object,

$v_0$ = initial velocity of the object,

Here,

$s_0=400\text{ feet}$

$v_0=35\text{ feet per sec}$

Hence, the height of the ball after t seconds,

$s(t)=-16t^2+35t+400$

When s(t) = 0,

$\implies -16t^2+35t+400=0$

$t=\frac{-35\pm \sqrt{35^2-4\times -16\times 400}}{2\times -16}$

$t=\frac{-35\pm \sqrt{1225+25600}}{-32}$

$\implies t\approx -4.02\text{ or }t\approx 6.21$

∵ Time cannot be negative,

Hence, after 6.21 seconds the ball will reach the ground.

4 0

3 years ago