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3 years ago

Part 50000 of me forgetting math please help

Mathematics

1 answer:

Citrus2011 [14]3 years ago

5 0

Answer:

Vertical Pair

Step-by-step explanation:

...............It's Vertical..........

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Can someone pls help me

Yuri [45]

Answer:

I'm not sure, but I'll try

Step-by-step explanation:

(Side)^2 = (Hypotenuse)^2 - (Side)^2

(Side)^2 = (9)^2 - ( √ 65 )^2

(Side)^2 = (81) - (65)

(Side)^2 = 16

Take root of answer

Side = √16

Side = 4

Answer = 4

6 0

3 years ago

ln(y+1)-lny=1+3lnx . Express y in terms of x, in a form not involving logarithms. (4 marks, Maths CIE A level)

Delicious77 [7]

$remember$
$ln(x)=log_e(x)$
$and$
$log_x(a)-log_x(b)= log_x( \frac{a}{b} )$
$and$
$log_a(b)=c$ means $a^c=b$
$and$
$blog(a)=log(a^b)$

$so$

$ln(y+1)-ln(y)=1+3ln(x)$
$ln( \frac{y+1}{y} )=1+ln(x^3)$

$minus$ $ln(x^3)$ $from$ $both$ $sides$

$ln( \frac{y+1}{y}-ln(x^3) )=1$
$ln( \frac{y+1}{yx^3})=1$
$log_e( \frac{y+1}{yx^3})=1$

$translate$

$e^1=\frac{y+1}{yx^3}$
$e=\frac{y+1}{yx^3}$

$times$ $both$ $sides$ $by$ $yx^3$

$eyx^3=y+1$

$minus$ $y$ $from$ $both$ $sides$

$eyx^3-y=1$
$y(ex^3-1)=1$

$divide$ $both$ $sides$ $by$ $(ex³-1)$

$y= \frac{1}{ex^3-1}$

6 0

3 years ago

Read 2 more answers

How to solve the problem

WINSTONCH [101]

As tgose lines are parallel then,

a = 140° ( by alternate interior angles)

then,
tha angle just below "a" on the other paralle line would also be 140° by corresponding angles,

using exterior angle property of triangle

66° + b = 140°

b = 140° -66
= 74°

7 0

3 years ago

Help me please geometry class

artcher [175]

Answer:

m∠ADB = 59°

Step-by-step explanation:

I've provided my work which also includes how I check my answers by using the information given! Hope this helps!!! If you have any questions, I can try to help.

6 0

3 years ago

If you combined these two polygons what new polygon could you create

Serjik [45]

You would create a square

3 0

3 years ago

Read 2 more answers