We can work out the first three terms of this quadratic equation with substitution.
The first term of this sequence is where n=1, we can substitute 1 in for n
y=1^2+2(1)-4
y=1+2-4
y=-1
We can do this for the next two terms as well
y=2^2+2(2)-4
y=4+4-4
y=4
For the last term:
y=3^2+2(3)-4
y=9+6-4
y=11
270/630=x/100
630x=270000
x=27000/630
=42.9%
Total outcomes=6 i.e{1,2,3,4,5,6 }
No.of favourable outcomes = 3 i.e {I, 3,5}
P(odd)=3/6=1/2
Step-by-step explanation:
26/7 ×35/ 8 =910/56
=16 1 /4
61/9 × 23 /4 =1403 / 36
=38 35/36
Answer:
Step-by-step explanation:
u = ?
a = 3.75m/s^2
t = 2 s
v = 9375m/s
a = v-u/t
3.75 = 9375 - u / 2
3.75 × 2 = 9375 - u
7.5 = 9375 - u
u = 9375 - 7.5
=<em> 9367.5 m/s</em>
<em>Hope this helps</em>
<em>plz mark as brainliest!!!!!!!</em>
