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Kryger [21]
3 years ago
5

Three friends go grocery shopping together, and each buys the same kind of strawberries. Akio buys 2 pounds (lb) and pays $1.50.

Gordon buys 3 pounds and pays $2.25. Maria buys 4 pounds and pays $3.00. Identify the graph and unit price that represent the strawberry costs.

Mathematics
2 answers:
-BARSIC- [3]3 years ago
7 0

Answer:

The answer would be A because each pound costs 75 cents.

Step-by-step explanation:

konstantin123 [22]3 years ago
4 0

Answer:

it will be B

Step-by-step explanation:

because 1 lb is equal to .75 and the graph shows the exact process of if you were to keep adding .75

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For this case we have by definition, that the volume of a sphere is given by:

V = \frac {4} {3} \pi * r ^ 3

Where:

r: It is the radius of the sphere

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\frac {r} {3}:

V = \frac {4} {3} \pi * (\frac {r} {3}) ^ 3\\V = \frac {4} {3} \pi * \frac {r ^ 3} {27}\\V = \frac {4} {81} \pi * r ^ 3

ANswer:

the volume decreases considerably because the denominator increases

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3 years ago
What is the value of x in the equation X - 2.6 = 1.8?
Ivenika [448]

Step-by-step explanation:

Given

x - 2.6 = 1.8

x = 1.8 + 2.6

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Step-by-step explanation:

5 0
4 years ago
You have been asked to design a can shaped like right circular cylinder that can hold a volume of 432π-cm3. What dimensions of t
rosijanka [135]

Answer:

Height = 12cm

Radius = 6cm

Step-by-step explanation:

Given

Represent volume with v, height with h and radius with r

V = 432\pi

Required

Determine the values of h and r that uses the least amount of material

Volume is calculated as:

V = \pi r^2h\\

Substitute 432π for V

432\pi = \pi r^2h

Divide through by π

432 = r^2h

Make h the subject:

h = \frac{432}{r^2}

Surface Area (A) of a cylinder is calculated as thus:

A=2\pi rh+2\pi r^2

Substitute \frac{432}{r^2} for h in A=2\pi rh+2\pi r^2

A=2\pi r(\frac{432}{r^2})+2\pi r^2

A=2\pi (\frac{432}{r})+2\pi r^2

Factorize:

A=2\pi (\frac{432}{r} + r^2)

To minimize, we have to differentiate both sides and set A' = 0

A'=2\pi (-\frac{432}{r^2} + 2r)

Set A' = 0

0=2\pi (-\frac{432}{r^2} + 2r)

Divide through by 2\pi

0= -\frac{432}{r^2} + 2r

\frac{432}{r^2} = 2r

Cross Multiply

2r * r^2 = 432

2r^3 = 432

Divide through by 2

r^3 = 216

Take cube roots of both sides

r = \sqrt[3]{216}

r = 6

Recall that:

h = \frac{432}{r^2}

h = \frac{432}{6^2}

h = \frac{432}{36}

h = 12

Hence, the dimension that requires the least amount of material is when

Height = 12cm

Radius = 6cm

3 0
3 years ago
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