Consecutive integers are numbers one after the other on the number one (ie. 1,2,3,4,5 or 203,204,205).
times= multiplication
sum= addition
more than= addition
is= equal sign
x= first integer
x+2= second integer
x+3= third integer
3(x + (x + 2))= 5(x + 3) + 8
add inside parentheses
3(2x + 2)= 5(x + 3) + 8
multiply 3 and 5 by their parentheses
(3*2x) + (3*2)= (5*x) + (5*3) + 8
multiply in parentheses
6x + 6= 5x + 15 + 8
6x + 6= 5x + 23
subtract 5x from both sides
x + 6= 23
subtract 6 from both sides
x= 17 first integer
x + 1= 17 + 1= 18 second integer
x + 2= 17 + 2= 19 third integer
CHECK:
3(x + (x + 2))= 5(x + 3) + 8
3(17 + (17 + 2))= 5(17 + 3) + 8
3(17 + 19)= 5(20) + 8
3(36)= 100 + 8
108= 108
ANSWER: The three consecutive integers are 17, 18 and 19.
Hope this helps! :)
The sequence is arithmetic as it goes down 3 every time
Arithmetic nth term formula is an=a1+d(n-1)
an=7-3(n-1)
an=7-3n+3
an=-3n+10
To find the 100th term substitute n for 100
a100=-3(100)+10
a100=-300+10
a100=-290
The 100th term is -290
115 is the correct answer.
I saw the diagram earlier :)
Hope this helps, have a great day, and God bless.
Brainliest is always appreciated :)
