All categories

3 years ago

What are the real solutions to the equation 5x2 + 29x + 20 = 0?

Mathematics

2 answers:

lbvjy [14]3 years ago

8 0

Answer: -30/29

Step-by-step explanation: Let's solve your equation step-by-step.

(5)(2)+29x+20=0

Step 1: Simplify both sides of the equation.

(5)(2)+29x+20=0

10+29x+20=0

(29x)+(10+20)=0(Combine Like Terms)

29x+30=0

Step 2: Subtract 30 from both sides.

29x+30−30=0−30

29x=−30

Step 3: Divide both sides by 29.

29x/29=-30/29

Minchanka [31]3 years ago

5 0

Answer:Solutions are: x = -5, x = -4/5.

Step-by-step explanation:

You might be interested in

How many ways can a dance instructor send 4 of her 11 students to a summer dance program?

Sedaia [141]

Answer:

d) 330

Step-by-step explanation:

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is C(11 , 4)

That is $11_{C_{4} }$ ways

by using formula $n_{C_{r} } = \frac{n!}{(n-r)!r!}$

now simplification

$11_{C_{4} } = \frac{11!}{(11-4)!4!}$

= $\frac{11X10X9X8X7!}{(7!)4X3X2X1}$

after cancelling 7! and on simplification

= $\frac{11X10X9X8}{4X3X2X1}$

after cancellation we get 330 ways

The number of ways can a dance instructor send 4 of her 11 students to summer dance program is 330

8 0

3 years ago

Find the exact value of sin (arccos(-3/4))

Arturiano [62]

The exact value is
sin(arccos(3/4))The equation for cosine is cos(A)=AdjacentHypotenuse. The inside trig function is arccos(3/4), which means cos(A)=3/4. Comparing cos(A)=AdjacentHypotenuse with cos(A)=3/4, find Adjacent=3 and Hypotenuse=4. Then, using the pythagorean theorem, find Opposite=√7.Adjacent=3Opposite=√7Hypotenuse=4Substitute in the known variables for the equation sin(A)=OppositeHypotenuse.sin(A)=√7 over 4Simplify.√7 over 4

6 0

3 years ago

Please Help me. Also if you could show your work thatd be great.

Over [174]

Answer:

3) $all \: real \: numbers$ , $( - \infty , \infty )$ , or $- \infty \leqslant x \leqslant \infty$ (same thing)

4) $- \infty < y < 0$ or $( - \infty ,0)$ (same thing)

5) $-2$ or $(0, -2)$ (same thing)

Step-by-step explanation:

3) Domain represents the amount of $x$ -values in a function. The image shows that the function's arrows point in both directions (right and left), infinitely, so the domain would be $all \: real \: numbers$ , $( - \infty , \infty )$ , or $- \infty \leqslant x \leqslant \infty$ (same thing).

4) Range represents the amount of $y$ -values in a function. The function goes downward forever ( $- \infty < y$ ) by the indication of an arrow and halts just under the y-axis ( $y < 0$ ). After combining these two inequalities, you see that the range is $- \infty < y < 0$ or $( - \infty ,0)$ (same thing).

5) The $y$ -intercept is where the function crosses the $y$ -axis. In this function, the $y$ -intercept is $-2$ or $(0, -2)$ (same thing).

5 0

3 years ago

Math test!!! please help!!! pick abc or d

Soloha48 [4]

Answer:

Step-by-step explanation:

i took the test

4 0

3 years ago

Read 2 more answers

Find a polynomial, which, when added to the polynomial 5x^2–3x–9, is equivalent to x^2-5x+6

alexandr1967 [171]

So this is easy counting
so 5x^2-3x-9
we have 5 x^2's
-3 x's
-9

wat do we add to that to get
1 x^2's
-5 x's
+6
so we do each
5x^2+what=1x^2
subtract 5x^2
from both sides
what=-4x^2
first is -4x^2

then we have -3x to -5x
-3x+what=-5x
add 3x to both sides
what=-2x
second is -2x

-9 to 6
-9+ what=6
ad d9
what=15
last is 15
thereffor add -4x^2-2x+15

6 0

3 years ago

What are the real solutions to the equation 5x2 + 29x + 20 = 0?​

What are the real solutions to the equation 5x2 + 29x + 20 = 0?