Answer:
Ambitious
In this case, you have to multiply the price of the one way journey ($2.65) by 8 (as this is the number of individual journeys made in one week. It's gives you $21.20. As he has 1 bottle of water at $1.45 each day for four days, you have to multiply these together, giving you $5.80 You then have to add together $21.20 and $5.80, giving you $27. Therefore, it costs Edgar $27 a week
Step-by-step explanation:
Answer:
x= 21
y= 3
z= 21
Step-by-step explanation:
Let the center be O,
=> Triangle AOD is an Isosceles triangle so AO≅DO, "21 = x"
=> Line AC is divided in two equal parts by the center so if AO= 21 then
7y = 21, and thus "y = 3"
=> BOC is also an Isosceles triangle so CO ≅ BO, if CO = 21 (7y → 7*3) then so will be BO. Therefore "z = 21"
Answer:
The current price of the unit trust = £13,831.72
Step-by-step explanation:
Since it increased 7% per annum in last three years and decreased by 3% per annum before that, it implies that the unit trust decreased by 3% per annum for the first 2 years and then increased by 7% per annum for the next 3 years in the total 5 year period
The invested after 2 years = 12,000*(1-0.03)^2 = £11,290.8
This amount then grows by 7% for the next 3 years making it = 11,290.80*(1+0.07)^3 = £13,831.7155 = £13,831.72 (Rounded to 2 decimals)
The current price of the unit trust = £13,831.72 (Rounded to 2 decimals)
Answer:
We accept H₀
Step-by-step explanation:
Normal Distribution
size sample n = 69
sample mean 18.94
standard deviation 8.3
Is a one tailed-test to the left we are traying of find out is we have enough evidence to say that the mean is less than 20 min.
1.-Test hypothesis H₀ ⇒ μ₀ = 20
Alternative hypothesis Hₐ ⇒ μ₀ < 20
2.- Critical value
for α = 0.1 we find from z Table
z(c) = - 1.28
3.-We compute z(s)
z(s) = [ ( μ - μ₀ ) / (σ/√n) ⇒ z(s) = [( 18.94 - 20 )*√69)/8.3]
z(s) = ( -1.06)*8.31/8.3
z(s) = - 1.061
4.- We compare
z(c) and z(s) -1.28 > -1.061
Then z(c) > z(s)
z(s) in inside acceptance region so we accept H₀
13,822 to one significant figure is 10,000
623 to one significant figure is 600
14 to one significant figure is 10
10,000 times 600 = 6,000,000
6,000,000/10 = 600,000
