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SVETLANKA909090 [29]
3 years ago
14

If p/q is a rational number then p cannot be equal to 0 true or false please fast urgent.......

Mathematics
1 answer:
GaryK [48]3 years ago
6 0

Answer:

False

Step-by-step explanation:

If p=0,  \frac{p}{q} is equal to 0 and 0 is a rational number

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Write the slope-intercept form of the equation of the line perpendicular to the
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find the x-intercepts of the parabola with vertex(6,27) and y-intercept (0,-81). write answer in form (x1,y1)(x2,y2). if necessa
sergey [27]
The vertex form of the equation is:
y = a ( x - h )² + k
- 81 = a ( 0 - 6 )² + 27
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a = - 3
y = - 3 ( x - 6 )² + 27
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y = - 3 x² + 36 x - 108 + 27
y = - 3 x² + 36 x - 81
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x ( x - 9 ) - 3 ( x - 9 ) = 0
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7 0
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Read 2 more answers
find the equations of the tangents to the curve y= x(x-1)(x+2) at the points where the curve cuts the x axis
antoniya [11.8K]

First of all, we compute the points of interest, i.e. the points where the curve cuts the x axis: since the expression is already factored, we have

x(x-1)(x+2) = 0 \iff x=0\ \lor\ x-1=0\ \lor\ x+2=0

Which means that the roots are

x=0\ \lor\ x=1\ \lor\ x=-2

Next, we can expand the function definition:

y = x(x-1)(x+2) = x^3 + x^2 - 2x

In this form, it is much easier to compute the derivative:

y' = 3x^2+2x-2

If we evaluate the derivative in the points of interest, we have

y'(-2) = 6,\quad y'(0)=-2,\quad y'(1)=3

This means that we are looking for the equations of three lines, of which we know a point and the slope. The equation

y-y_0=m(x-x_0)

is what we need. The three lines are:

y-0=6(x+2) \iff y = 6x+12  This is the tangent at x = -2

y-0=-2(x-0) \iff y = -2x  This is the tangent at x = 0

y-0=3(x-1) \iff y = 3x-3  This is the tangent at x = 1

7 0
2 years ago
Given f(x) = 18x + 8, find x when f(x)= 14.
Naddika [18.5K]

The answer is 0.3 (1/3.)

Proof?

f(0.3) = 18(0.3) + 8

f(0.3) = 6 + 8

f(0.3) = 14

14 = 14

⭐ Please consider brainliest! ⭐

✉️ If any further questions, inbox me! ✉️

8 0
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