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Nimfa-mama [501]
3 years ago
11

ABC is rotated 180º using the origin as the center of rotation.

Mathematics
1 answer:
kogti [31]2 years ago
3 0

Answer:

ejbf 1037 2049y 29rh

Step-by-step explanation:

jsu31j 2984 e84ube e94bg.

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Given the sample −4, −10, −16, 8, −12, add one more sample value that will make the mean equal to 3.
Agata [3.3K]

Answer: The value to add to the set is 52

=======================================================

For a moment, ignore the extra value we'll add in later.

The given set of values add to -34.

Let x be the extra value we add in. It adds to the -34 to get -34+x, then we divide by 6 because the set {-4,-10,-16,8,-12,x} has 6 items.

So we get the mean (-34+x)/6

Set this equal to the mean we want (3) and solve for x

(-34+x)/6 = 3

-34+x = 6*3

-34+x = 18

x = 18+34

x = 52

The set {-4,-10,-16,8,-12,x} updates to {-4,-10,-16,8,-12,52} and this set has a mean of 3.

6 0
3 years ago
The vertices of polygon ABCD are at A(1,1), B(2,3), C(3,2), and D(2,1). ABDC is reflected across the x-axis and translated 2 uni
velikii [3]

Answer:


Step-by-step explanation:


A. (1,1)

B. (2, -1)

C. (3, 0)

D. (2,1)

yes so i have matched the vertices of the polygon

4 0
3 years ago
Read 2 more answers
A farmer has a bale of hay with mass of 36 kilograms. How many milligrams of hay are in the bale?
Ilia_Sergeevich [38]

KILO=1000.............. MILLI= thousandth

1kg is 1000 grams

1 milligram is one thousandth of a gram, so a 1 gram = 1000mg.

in 36 kg, then there are 36 * 1000 grams.

and in (36*1000) grams there are (36*1000)*1000 mg, 36,000,000 mg.

4 0
3 years ago
Complement and supplement of a 19
Tems11 [23]

well first the complement I 90-19=71

and supplement is 180-19=161

3 0
3 years ago
Which of the following tables shows the correct steps to transform x^2+6x + 8=0
Vlad1618 [11]
Perhaps the most concise way to factor is by "completing the square" which is how the quadratic formula is derived...

x^2+6x+8=0  move constant to other side, subtract 8 from both sides

x^2+6x=-8, halve the linear coefficient, square it, then add that to both sides, in this case (6/2)^2=3^2=9

x^2+6x+9=1  now the left side is a perfect square of the form

(x+3)^2=1  take the square root of both sides

x+3=±√1  subtract 3 from both sides

x=-3±√1

x=-3±1

x=-4 and -2

Since the zeros occur when x=-4 and -2 the factors of the equation are:

(x+2)(x+4)
7 0
3 years ago
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