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ArbitrLikvidat [17]
3 years ago
6

Johanna buys two poster frames that have the same area, but different shapes. One is a rectangular frame with a width of 40 inch

es and a length of 30 inches. The other frame is square. What a poster with dimensions of 36 inches X 36 inches fit in the square frame?
Mathematics
1 answer:
grandymaker [24]3 years ago
8 0

Answer:

No, the poster would not fit in the frame

Step-by-step explanation:

A rectangle is a quadrilateral (has 4 sides and 4 angles) with two pair of opposite and equal sides.

A square is a quadrilateral in which all sides are equal.

Given that the rectangular frame has a width of 40 inches and a length of 30 inches. The area of the rectangular frame is:

Area of rectangular frame = length * breadth = 40 inches * 30 inches = 1200 in²

Since the square frame has the same area as the rectangular frame, hence:

Area of square frame = length * length

length² = 1200

length = √1200 = 34.64

Therefore the dimensions of the square frame is 34.64 inches by 34.64 inches.

Hence a poster with dimensions of 36 inches X 36 inches cannot fit in the square frame.

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Citrus2011 [14]

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Step-by-step explanation:

The formula for determining the circumference of a circle is expressed as

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The circumference of the inner circle is 44 ft. It means that

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4 years ago
Rozalie spent $26 at a parking garage in downtown Orlando. The garage charged a base free of $7.50 for the first hour and a hour
bagirrra123 [75]
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rate of change = $2.75
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2.75h + 7.5 = 26
($2.75/hour plus the base fee of $7.50 equals the total amount spent, $26)

Now just solve for h

2.75h + 7.5 = 26
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So the answer would be Rozalie spent about 6.73 hours at the garage.

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3 years ago
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Factor out 2 from the expression

Write 2x as a difference

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Finally,, distribute 2 through the parenthesis to find your answer

This means that the correct answer to your question is (x-2)/(2x+8)

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