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Thepotemich [5.8K]
2 years ago
15

The class of math is mapped on a coordinate grid with the origin being at the center point of the hall. Mary’s seat is located a

t the point (9, -8) and Betty’s seat is located at (5, -10). How far is it from Mary’s seat to Betty’s seat?
SOMONE PLS HELP ME WITH THIS
Mathematics
1 answer:
nignag [31]2 years ago
7 0
To find the distance b/t 2 points you need to use the distance formula. that is

distance = square root of (x2-x1)^2 + (y2-y1)^2


to fill it in, it is

(it doesnt matter which point you start with, as long as its consistent)

x1 = 9
x2 = 5
y1 = -8
y2 = -10

square root of (5-9)^2 + (-10-8)^2

lets do algebra!

square root of (-4)^2 + (-18)^2

square root of 16 + 324

square root of 340


Distance = 18.4391 units.

I hope this helps!
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1725

Step-by-step explanation:

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What is the value of x when h(x) = −3?
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Answer:

○ -1

Step-by-step explanation:

Looking closely at this piecewise function, when the line on the left-hand side intersects at -3 = y, x is -1.

i hope this work for you

8 0
2 years ago
Let W be part of the solid sphere of radius 4, centered at the origin, that lies above the plane z = 2. Set up an integral in cy
andriy [413]

Answer:

V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π

Step-by-step explanation:

Since we have the radius of the sphere R = 4, we have R² = r² + z² where r = radius of cylinder in z-plane and z = height² of cylinder.

So, r = √(R² - z²)

r = √(4² - z²)

r = √(16 - z²)

Since the region is above the plane z = 2, we integrate z from z = 2 to z = R = 4

Our volume integral in cylindrical coordinates is thus

V = ∫∫∫rdrdθdz integrating from z = 2 to z = 4, r = 0 to √(16 - z²) and θ = 0 to 2π

4 0
2 years ago
a sign in front of a roller coaster say '' you must be 40 inches tall to ride" what percentage of 54 inches of this is?
cupoosta [38]
The 54 percentage of 40 inches is 21.6 inches
5 0
2 years ago
Eugenia walked all the way to school at 3 mph then realized she forgot her math book (how could she?!), so she ran back at 7 mph
kondor19780726 [428]

Let us say distance between Eugenia's home and school is x miles.

Speed of Eugenia when she walked from home to school = 3 mph

Speed of Eugenia when she walked from school to home = 7 mph

Total time taken = 45 minutes or 0.75 hours

We know that the speed distance formula is given by:

speed=\frac{distance}{time}

time=\frac{distance}{speed}

Time taken by Eugenia when she walked from home to school = x/3 hours

Time taken by Eugenia when she walked from school to home = x/7 hours

Total time taken = x/3+x/7

So forming an equation we have,

\frac{x}{3}+\frac{x}{7}=0.75

Taking lcd of 7 and 3 as 21,

\frac{7x}{21}+\frac{3x}{21}=0.75

\frac{10x}{21}=0.75

10x=15.75

Dividing both sides by 10 , we have

x= 1.575

Answer: So we can say that the distance between Eugenia's house and school is 1.575 miles.




4 0
3 years ago
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