Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that
Standard deviation, ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.
Assume the bag weight distribution is bell-shaped
Therefore,
We know that
Using the value of z
Now,
Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Answer:
26.6667 minutes or 0.444 hours per activity.
Step-by-step explanation:
If he spent an equal amount of time on each activity, then it would have to be divided equally: 4hours/9
In minutes:
4 x 60 = 240 minutes
240/9
26.6667 minutes per activity.
In Hours:
4/9
0.444 hours per activity.
Use Pythagoras 6 squared =36-(4x4) =20 square root of 20 then times that by two
Add the two angles and set them equal to 180, them solve for x