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sashaice [31]
3 years ago
14

If x = -8, then which of the following equations makes a true statement?

Mathematics
1 answer:
Sindrei [870]3 years ago
6 0
It would be B. Because if x = -8 2x= -16-2 would be-18
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Can someone please help me with this
LenKa [72]

Just guess and check. For example, for the first on the left, I guessed 3 to begin with. 3 + 3 + 3 = 9, but 10 + 3 = 13, so 3 is not the answer. I then guessed 5. 5 + 5 + 5= 15, and 10 + 5= 15, so star = 5.

4 0
3 years ago
Frequency (y) varies inversely with wavelength (x). Find the frequency (measured in THz ) of blue light if its k value is 175,72
horsena [70]

We have been that frequency (y) varies inversely with wavelength (x).

We know that two inversely proportional quantities are in form a=\frac{k}{b}, where a is inversely proportional to b and k is constant of variation.

Our required equation would be y=\frac{k}{x}.

To find frequency of blue light, we will substitute k=175,720 and x=230 in our equation as:

y=\frac{175,720}{230}

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8 0
4 years ago
So in numeric form what is 700,000+40,000+9000+200 and +50
WARRIOR [948]

Answer: 749,250

Step-by-step explanation:

700,000 + 40,000= 740,000.

9,000+200+50= 9,250.

740,000 + 9,250 = 740,250.

4 0
4 years ago
Read 2 more answers
Marissa used the set of ordered pairs below to graph a relation.
KIM [24]

0, 2, 3, 4, 6

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4 0
3 years ago
I don’t understand what this question is asking for
Elden [556K]

Answer:

  (d)  m∠AEB = m∠ADB

Step-by-step explanation:

The question is asking you to compare the measures of two inscribed angles. Each of the inscribed angles intercepts the circle at points A and B, which are the endpoints of a diameter.

__

<h3>applicable relations</h3>

Several relations are involved here.

  • The measures of the arcs of a circle total 360°
  • A diameter cuts a circle into two congruent semicircles
  • The measure of an inscribed angle is half the measure of the arc it intercepts
<h3>application</h3>

In the attached diagram, we have shown inscribed angle ADB in blue. The semicircular arc it intercepts is also shown in blue. A semicircle is half a circle, so its arc measure is half of 360°. Arc AEB is 180°. That means inscribed angle ADB measures half of 180°, or 90°. (It is shown as a right angle on the diagram.)

If Brenda draws angle AEB, it would look like the angle shown in red on the diagram. It intercepts semicircular arc ADB, which has a measure of 180°. So, angle AEB will be half that, or 180°/2 = 90°.

The question is asking you to recognize that ∠ADB = 90° and ∠AEB = 90° have the same measure.

  m∠AEB = m∠ADB

_____

<em>Additional comment</em>

Every angle inscribed in a semicircle is a right angle. The center of the semicircle is the midpoint of the hypotenuse of the right triangle. This fact turns out to be useful in many ways.

7 0
2 years ago
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