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tresset_1 [31]
3 years ago
10

Please explain how to do this!

Mathematics
1 answer:
irakobra [83]3 years ago
5 0
Ask ur mom she can knows
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Pls help me ASAP !!!!!!!!!
allochka39001 [22]
Hopefully this help

8 0
2 years ago
What is the value represented by the letter A on the box plot of data?
Lady_Fox [76]
Answer: A = 5

The Wise Orange found an image that may be helpful:

7 0
3 years ago
Read 2 more answers
A rocket is launched straight up from the ground with an initial velocity of 192 feet per second. The equation for the height of
Ivenika [448]

The equation for the height of the rocket at time t given

h= -16t^2+192t

We have to find the time t, when the rocket reaches 560 feet.

That means we have to find t when h = 560 ft. we will place 560 in the place of h to find t now.

h= -16t^2+192t

560 = -16t^2+192t

In the right side, we can check -16 is the common factor. So we will take out -16 from the rigbht side.

560 = -16(t^2 - 12t)

To get rid of -16 from the right side and move it to left side, we will divide both sides by -16.

560/-16 = -16(t^2-12t)/-16

-35 = t^2 -12t

Now we will move -35 to the righ side by adding 35 to both sides.

-35+35 = t^2-12t+35

0 = t^2 -12t+35

t^2-12t+35 = 0

We will factorize thee left side to find the values of t now. We need to find a pair of factors of 35 that by adding them we will get -12.

The pair of factors of 35 are -5 and -7 and by adding -5-7 we will get -12.

t^2-12t+35 =0

(t-5)(t-7) =0

So by using zero product property we will get

t-5 =0

t-5+5 = 0+5

t=5

Also t-7 =0

t-7+7 = 0+7

t=7

So we have got the rocket reaches at 560ft when t = 5 seconds and also when t = 7 seconds.

Now part b.

When the rocket completes its trajectory and hits the ground then the height or h = 0. So we will place h = 0 there in the equation.

h= -16t^2+192t

0= -16t^2 + 192 t

0 = -16(t^2-12t)

-16(t^2-12t) = 0

We will move -16 to the other side by dividing it to both sides.

-16(t^2-12t)/-16 = 0/-16

t^2-12t = 0

We will take out the common factor t from the left side. By taking out t we will get,

t(t-12) = 0

We will use zero product property now. By using that we will get,

t = 0

ans also t-12 = 0

t-12+12 = 0+12

t = 12

When the rocket completes its trajectory and hits the ground the time t can not be 0. When t =0, the rocket starts the trajectory.

So when the rocket completes its trajectory and hits the ground ,

then t = 12seconds.

So we have got the required answers.

6 0
3 years ago
If you are smart put this emojiif u not smart put this emoji ok thanks
PtichkaEL [24]
Yesssss that is right
3 0
3 years ago
Read 2 more answers
-8= 3-5(x+6) solving algebraicaily​
SOVA2 [1]

Let's solve your equation step by step

-8=3-5(x+6)

Step 1: simplify both sides of the equation

-8=3-5(x+6)

-8=3+(-5)(x)+(-5(6) (distribute)

-8=3+-5x+-30

-8=(-5x)+(3+-30) (combine like terms)

-8=-5x+-27

-8=-5x-27

Step 2: flip the equation

-5x-27=-8

Step 3: add 27 to both sides

-5x-27+27=-8+27

-5x=19

Step 4: Divide both sides by -5

-5x/-5 = 19/-5

Answer : x= -19/5

4 0
3 years ago
Read 2 more answers
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