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lana [24]
3 years ago
10

A ship leaves port at noon and travels at a bearing of 214°. The ship’s average rate of speed is 15 miles per hour.

Mathematics
1 answer:
Daniel [21]3 years ago
3 0

Answer: (-31.09 mi, -20.97 mi)

Step-by-step explanation:

If the noon is our initial time, then we have that 2:30 pm is t = 2.5 hours.

Now, the position (x, y) of the ship can be writen as:

(velocity*time*cos(angle), velocity*time*sin(angle))

or:

(15mph*t¨*cos(214°), 15mph*t*sin(214°))

then the position at t = 2.5 hours is:

(15mph*2.5h*cos(214°), 15mph*2.5h*sin(214°))

(-31.09 mi, -20.97 mi)

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Two buildings are facing each other on a road of width 12 metre . From the top of the first building, which is 10 metre high , t
Karo-lina-s [1.5K]

Answer:

\displaystyle 10 + 12\sqrt{3} <em>metres</em>

Step-by-step explanation:

You are finding the <em>height</em><em> </em>of the building with an angle of elevation, therefore we need to solve for <em>EC</em><em> </em>to add it to <em>BA</em><em> </em>[10 metres] and use TRIGONOMETRIC RATIOS to arrive at our conclusion. Just in case you have forgotten what they were, here they are:

\displaystyle \frac{OPPOSITE}{HYPOTENUSE} = sin\:θ \\ \frac{ADJACENT}{HYPOTENUSE} = cos\:θ \\ \frac{OPPOSITE}{ADJACENT} = tan\:θ \\ \frac{HYPOTENUSE}{ADJACENT} = sec\:θ \\ \frac{HYPOTENUSE}{OPPOSITE} = csc\:θ \\ \frac{ADJACENT}{OPPOSITE} = cot\:θ

We can now solve for <em>EC</em>:

\displaystyle cot\:60 = \frac{12}{EC} → ECcot\:60 = 12 \\ \\ \frac{ECcot\:60}{cot\:60} = \frac{12}{cot\:60} → 12\sqrt{3} = EC

<em>OR</em>

\displaystyle tan\:60 = \frac{EC}{12} → 12tan\:60 = EC → 12\sqrt{3} = EC

Now that you have solved for <em>EC</em>, you can now add it to your original 10 metres to get \displaystyle 10 + 12\sqrt{3} <em>metres</em>. As a decimal, you would get \displaystyle 30,78460969... <em>metres</em>. You can go ahead and round this off if necessary.

** The reason why the <em>cotangent</em><em> </em>[or <em>tangent</em>] ratio was used was because <em>EA</em><em> </em>is equivalent to <em>DB</em> by the definition of a rectangle. It has two pairs of parallel and congruent sides with <em>four</em><em> </em><em>right</em><em> </em><em>angles</em>. Plus, that is the <em>adjacent</em><em> </em><em>side</em><em> </em>of the triangle, while <em>EC</em><em> </em>is the <em>opposite</em><em> </em><em>side</em><em> </em>of the triangle, so we knew our ratios were correct.

I am joyous to assist you at any time.

8 0
2 years ago
A waiter receives tips from each customer. On average, the tip is 15% of the customer’s bill. At this rate, which of the followi
Lelechka [254]

Answer:

C) $12.00

Step-by-step explanation:

Take the price of the bill

78.20

Find 10 %

78.20 * .1

7.82

Take half ( which is 5%)

3.91

Add the two amounts together

7.82+3.91

11.73

Rounding to the nearest dollar

12.00

OR

Round the bill to 80.00

Take 15%

80 * .15

12.00

4 0
3 years ago
The sum of three numbers is 96. The third number is 6 less than the first. The second number is 3 times the third. What are the
11Alexandr11 [23.1K]
Let the first number be x.

Third number = x - 6

Second number = 3(x - 6) = 3x - 18

Sum of the numbers = 96

x + 3x - 18 + x - 6 = 96

5x -24 = 96

5x = 120

x = 24

Thus,

The first number is 24. The second number is 54. The third number is 18.
6 0
3 years ago
Which function is a linear function a. 1-3x^2 b. y+7=5x c. x^3 + 4 = y d. 9(x^2-y) = 3 e.y-x^3=8
FrozenT [24]

Answer:

b. y+7=5x

Step-by-step explanation:

a. 1-3x^2     is a quadratic

b. y+7=5x    is a linear function:  y = 5x - 7

c. x^3 + 4 = y   is a cubic function

d. 9(x^2-y) = 3    is a quadratic function

e.y-x^3=8   is a cubic function

3 0
3 years ago
Find the value of x if B is the midpoint of AC, AB = 2x + 9 and BC = 37.
Leno4ka [110]

Answer:

14

Step-by-step explanation:

B is the midpoint of AC, in other words it is the halfway point.

So A to B should be equal to B to C

Our expression is:

2x + 9 = 37

Subtract 9

2x = 28

Divide by 2

x = 14

5 0
3 years ago
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