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Ksenya-84 [330]
3 years ago
6

Question is below (wasn't sure about the answer)

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer: Choice A)

H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

=================================================

Work Shown:

SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

This is not the only way to solve for H.

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You open a book to two facing pages. The product of the two pages is 600. Find the page numbers.
Ivan
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yaroslaw [1]

It looks like the given equation is

sin(2x) - sin(2x) cos(2x) = sin(4x)

Recall the double angle identity for sine:

sin(2x) = 2 sin(x) cos(x)

which lets us rewrite the equation as

sin(2x) - sin(2x) cos(2x) = 2 sin(2x) cos(2x)

Move everything over to one side and factorize:

sin(2x) - sin(2x) cos(2x) - 2 sin(2x) cos(2x) = 0

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Then we have two families of solutions,

sin(2x) = 0   or   1 - 3 cos(2x) = 0

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(where n is any integer)

[2x = 2nπ   or   2x = π + 2nπ]

… … …   or   [2x = arccos(1/3) + 2nπ   or   2x = -arccos(1/3) + 2nπ]

[x = nπ   or   x = π/2 + nπ]

… … …   or   [x = 1/2 arccos(1/3) + nπ   or   x = -1/2 arccos(1/3) + nπ]

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