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Ksenya-84 [330]
3 years ago
6

Question is below (wasn't sure about the answer)

Mathematics
1 answer:
Paha777 [63]3 years ago
3 0

Answer: Choice A)

H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

=================================================

Work Shown:

SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

This is not the only way to solve for H.

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Refer to the attachment and solve
Gekata [30.6K]

Answer:

-8\frac{5}{8}

Step-by-step explanation:

\frac{-27}{4} +\frac{-15}{8}

\frac{-54}{8} +\frac{-15}{8}

\frac{-54-15}{8}

\frac{-69}{8}

-8\frac{5}{8}

6 0
3 years ago
Y = x - 3 and y = 7x + 3 on a graph
dusya [7]

Answer:

Y+x-3 and y=7x+3 on a graph

Step-by-step explanation:

2948 28942

4 0
3 years ago
Charlie invests £1200 at 3.5% per annum compound interest.
lbvjy [14]

Answer:

<h2>£1,330.46</h2>

Step-by-step explanation:

Using the compound interest formula A = P(1+\frac{r}{n} )^{nt}

A = amount compounded after n years

P = principal (amount invested)

r = rate (in %)

t = time (in years)

n = time used to compound the money

Given P =  £1200., r = 3.5%, t = 3years, n = 1 year(compounded annually)

A = 1200(1+0.035)^{3}\\ A = 1200(1.035)^{3}\\ A = 1200* 1.108717875\\A = 1,330.46

Value of Charlie's investment after 3 years is £1,330.46

6 0
3 years ago
Factor 1/10 out of 1/10x+9/10
notka56 [123]

Answer:

0.800

Step-by-step explanation:

6 0
3 years ago
Right triangles are similar. Always Sometimes Never
zavuch27 [327]

Answer:

Always

Step-by-step explanation:

Right triangles are always similar.

All right triangles have a 90 degree angle.

This means that, they would all look visually similar because of the 90 degree angle.

4 0
4 years ago
Read 2 more answers
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