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Ksenya-84 [330]
2 years ago
6

Question is below (wasn't sure about the answer)

Mathematics
1 answer:
Paha777 [63]2 years ago
3 0

Answer: Choice A)

H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

=================================================

Work Shown:

SA = 2(LW + LH + HW)\\\\2(LW + LH + HW) = SA\\\\LW + LH + HW = \frac{SA}{2}\\\\LH + HW = \frac{SA}{2} - LW\\\\H(L + W) = \frac{SA}{2} - LW\\\\H = \frac{\frac{SA}{2} - LW}{(L + W)}\\\\H = \frac{SA}{2(L+W)} - \frac{LW}{L+W}\\\\

This is not the only way to solve for H.

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It is given that cos 0 = -0.4209 and 0° 0 < 360°. Calculato the values of 0​
beks73 [17]

Answer:

114.89 degrees

245.11 degrees

Step-by-step explanation:

cos is negative in the second and third quadrant ("pointing" on the x-axis to the left).

so, the first answer for the second quadrant is

114.89 degrees.

the answer for the third quadrant is then backwards the same angles from a full 360 degree rotation

360 - 114.89 = 245.11 degrees

5 0
3 years ago
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Pavel [41]

Answer: 18

Step-by-step explanation:

5 0
3 years ago
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Suppose that .06 of each of two populations possess a given characteristic. Samples of size 400 are randomly drawn from each pop
omeli [17]

Answer:

The correct answer to the following question will be "0.0367".

Step-by-step explanation:

The given values are:

p1=p2=0.06

q1=q2=1-p1=0.94

n1=n2=400

As we know,

E(p1-p2)=p1-p2=0\\

SE(p1-p2)=\sqrt{\frac{p1q1}{n1}+\frac{p2q2}{n2}}

On putting the given values in the above expression, we get

                   = \sqrt{p1q1(\frac{1}{400}+\frac{1}{400})}

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Now, consider

P(p1-p2>0.03)=P[\frac{(p1-p2)-E(p1-p2)}{SE(p1-p2)}>\frac{0.03-0}{0.0168}]

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                            =P(Z>1-79)

                            =0.036727

Therefore, "0.0367" is the right answer.

8 0
2 years ago
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10 is in 3, so that's 30. There's another 9.

30 + 9 = 39.

39 tenths.
3 0
2 years ago
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The perimeter of triangle ABC
Scilla [17]
The perimeter of triangle ABC is: 54

21 + 18 + 15 =54
7 0
3 years ago
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