Answer:
8 possible microstates.
Explanation:
Supposed we tossed three (3) coins (a nickel, a dime, and a quarter).
The possible outcomes can be seen as follows.
Coin
1st. +1 +1 +1 -1 +1 -1 -1 -1
2nd +1 +1 -1 +1 -1 +1 -1 -1
3rd +1 -1 +1 +1 -1 -1 +1 -1
There 8 (eight) microstates are possible.
Answer:
wave length=speed/frequency
=345/229
The main difference between the two is that emission spectrum has different colored lines in the spectrum, an absorption spectrum has dark colored lines in the spectrum.
There are two types of vesicular transport processes, exocytosis and endocytosis. Endocytosis is the process which is involved in the toxin entering the neuron. This process is where cells intake waste or chemical transmitters which are suspended or dissolved in the extracellular fluid around the cell. <span />
To solve this question,
let us first calculate how much all the nucleons will weigh when they are apart,
that is:
<span>Mass of 25 protons = 25(1.0073) = 25.1825 amu </span>
Mass of neutrons = (55-25)(1.0087) = 30.261 amu
So, total mass of nucleons = 30.261+25.1825 =
55.4435 amu
<span>Now we subtract the mass of nucleons and mass of the Mn
nucleus:
55.4435 - 54.938 = 0.5055 amu
This difference in mass is what we call as the mass defect of
a nucleus. Now we calculate the binding energy using the formula:</span>
<span> E=mc^2 </span>
<span>But first convert mass defect in units of SI (kg):
Δm = 0.5055 amu = (0.5055) / (6.022x10^26)
<span>Δm = 8.3942x10^-28 kg</span>
Now applying the formula,
E=Δm c^2
E=(8.3942x10^-28)(3x10^8)^2
E=7.55x10^-11 J</span>
Convert energy from Joules
to mev then divide by total number of nucleons (55):
E = 7.55x10^-11 J *
(6.242x10^12 mev / 1 J) / 55 nucleons
<span>E = 8.57 mev / nucleon</span>