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max2010maxim [7]
3 years ago
6

Add parentheses to the expression so that its value is 45:

Mathematics
1 answer:
Reil [10]3 years ago
5 0
Iiiitttt’s the first one
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if you’re using the inspection method, what constant term would you need in the numerator of this rational expression for to be
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A group of rowdy teenagers near a wind turbine decide to place a pair of
Marrrta [24]

Answer:

a) Hence the equation of the sinusoidal function that describes the height of the shorts in terms of time is y = 9 + 7* sin(\pi * t / 15 - \pi  / 6)

b) Hence the height of the shorts at exactly t = 10 minutes, to

the nearest tenth of a meter is 5.5 meters

Step-by-step explanation:

a) The wind turbine blade traverses a circular path as it rotates with time (t), whose time variation is given by the following trajectory equation :

x^2 + (y-yc)^2 = R^2 ,

where  

R = (16 m - 2 m)/2 (since diameter = maximum height - minimum height of the pink short)

= 14 m / 2

= 7 m (radius of the circle)

Also, center of the circle will be at (0, 2 + R) i.e (0,9)

So,  is the trajectory path equation to the circle

Let x = 7* cos(w*t + \phi ) & y = 9 + 7* sin(w* t + \phi) be the parametric form of the above circle equation which represent the position of the pink shorts at the tip of the blade at time t  

At t= 10s, y = 16 m so we have,

9 + 7 * sin(10* w + \phi) = 16 ---------------(1)

Also, at t= 25s, y =2 m so we have,

9 + 7* sin(25 * w +\phi) = 2--------------(2)

Solving we have, 10* w + \phi = \pi/2 & 25*w + \phi = 3*pi/2

15* w = \pi\\\\w = \pi/15 & \phi = \pi/2 - 10*\pi/15 = -\pi / 6  

Therefore y = 9 + 7* sin(\pi * t / 15 - \pi  / 6) is the instantaneous height of the pink short at time t ( in seconds)

b) At t= 10minutes = 10 * 60 s = 600s, we have,

y = 9 + 7 * sin(\pi * 600/15 - \pi / 6)\\\\= 9 + 7 * sin(40* \pi - \pi / 6)

= 5.5 meters (pink short will be at 5.5 meters above ground level at t= 10 minutes)

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3 years ago
Whats 28 11/14 in simplest form
damaskus [11]
Mixed # x denominator + numerator = imp. Fraction

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3 years ago
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3x-24=x+10
3x-x=24+10
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x=34:2=17
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Find the slope of the two points (6,5) and (9, 15)
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\bf (\stackrel{x_1}{6}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{9}~,~\stackrel{y_2}{15}) ~\hfill \stackrel{slope}{m}\implies \cfrac{\stackrel{rise} {\stackrel{y_2}{15}-\stackrel{y1}{5}}}{\underset{run} {\underset{x_2}{9}-\underset{x_1}{6}}}\implies \cfrac{10}{3}

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