Add parentheses to the expression so that its value is 45:

The period, T, of a pendulum of length l is given by T = f(l) = 2π√l/g, where g is a constant. Find f^-1.

snow_lady [41]

Answer:

When effective length (L) is constant, the time period (T) of oscillation of a simple pendulum is inversely proportional to the square root of the acceleration due to gravity (g) at a place of observation. So, T∝√1g when L is constant.

Step-by-step explanation:

5 0

4 years ago

Use multiplication or division of power series to find the first three nonzero terms in the Maclaurin series for each function.

Lunna [17]

Answer:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Step-by-step explanation:

GIven that:

$f(x) = 5e^{-x^2} cos (4x)$

The Maclaurin series of cos x can be expressed as :

$\mathtt{cos \ x = \sum \limits ^{\infty}_{n =0} (-1)^n \dfrac{x^{2n}}{2!} = 1 - \dfrac{x^2}{2!}+\dfrac{x^4}{4!}-\dfrac{x^6}{6!}+... \ \ \ (1)}$

$\mathtt{e^{-2^x} = \sum \limits^{\infty}_{n=0} \ \dfrac{(-x^2)^n}{n!} = \sum \limits ^{\infty}_{n=0} (-1)^n \ \dfrac{x^{2n} }{x!} = 1 -x^2+ \dfrac{x^4}{2!} -\dfrac{x^6}{3!}+... \ \ \ (2)}$

From equation(1), substituting x with (4x), Then:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}- \dfrac{(4x)^6}{6!}+...}$

The first three terms of cos (4x) is:

$\mathtt{cos (4x) = 1 - \dfrac{(4x)^2}{2!}+ \dfrac{(4x)^4}{4!}-...}$

$\mathtt{cos (4x) = 1 - \dfrac{16x^2}{2}+ \dfrac{256x^4}{24}-...}$

$\mathtt{cos (4x) = 1 - 8x^2+ \dfrac{32x^4}{3}-... \ \ \ (3)}$

Multiplying equation (2) with (3); we have :

$\mathtt{ e^{-x^2} cos (4x) = ( 1- x^2 + \dfrac{x^4}{2!} ) \times ( 1 - 8x^2 + \dfrac{32 \ x^4}{3} ) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1+ (-8-1)x^2 + (\dfrac{32}{3} + \dfrac{1}{2}+8)x^4 + ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + (\dfrac{64+3+48}{6})x^4+ ...) }$

$\mathtt{ e^{-x^2} cos (4x) = ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

Finally , multiplying 5 with $\mathtt{ e^{-x^2} cos (4x) }$ ; we have:

The first three nonzero terms in the Maclaurin series is

$\mathbf{ 5e^{-x^2} cos (4x) }= \mathbf{ 5 ( 1 -9x^2 + \dfrac{115}{6}x^4+ ...) }$

7 0

3 years ago

3. What is the goal of education—especially when it comes to history and human rights? Cite evidence from this text, your own ex

zysi [14]

Answer:

The goal for human rights is to education aims to do the following: Enhance the knowledge and understanding of human rights. Foster attitudes of tolerance, respect, solidarity, and responsibility. Develop awareness of how human rights can be translated into social and political reality.

(Evidence) -------›

"The following year, he immigrated to the United States and settled in Kansas City, Mo., where he married, had four children and became a successful importer of ladies' handbags. It would be 16 years before he began speaking publicly about the Holocaust, something he says he decided to do after talking to one of his neighbors."

8 0

3 years ago

Explain why there should be at least two lines given on any plane

QveST [7]

Answer:So they can form a angle

Step-by-step explanation:

6 0

3 years ago

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Can someone please help. I’ll give you brainlist if correct

Elanso [62]

Answer: x = 12, y = -8

Step-by-step explanation:

If you do substitution:

4(-y+4) + 6y = 0

-4y + 16 + 6y = 0

2y + 16 = 0

2y = -16

y = -8

x = -(-8) + 4

x = 8 + 4

x = 12

7 0

3 years ago

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