Answer:

- Multiply 5 by 5 to get your first parameter.

- Multiply 6 by 5 to get the denominator, or your second parameter.

- For the second fraction,
, you need to multiply both parameters by 2, similar to before, but we now must use a different number, otherwise, the denominators will not be the same.


- The last step is to put these numbers you gathered into fractions. The bigger number always goes on the bottom, referred to as the denominator, while the smaller number, referred to as the numerator, always goes on the top.


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Finally, the problem is solved. Now that the problem is solved, we review what we just learned <em>not through more problems, though.</em>
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<h3>What have we learned?</h3>
We learned how to efficiently make fractions' deominators match.
Questions related to this topic? Ask me in the comments box, please!
Answer:
miles
Step-by-step explanation:
Let the total miles traveled be x.
Now, for the first 0.5 miles total charge is = $3.50
Then, the remaining distance to be traveled
miles
For each additional 0.1 mile, the additional charge is $0.30
So, for
miles, the total additional charge will be
Then, including the $2 tip, the total fare will be
Now, given that total fare is $15, so,
miles
Answer:
y = −one twelfth(x − 2)2
Step-by-step explanation:
y = −one twelfth(x − 2)2
Hello there!
Number 1 is C (11, 4) Image is below
I don't know number 2, so so sorry!
Number 3 is A. 36 The formula for perimeter of a rectangle is (2 * base) + (2 * height)
The base = 13
The height = 5
(5 * 2) + (13 * 2)
10 + 26 = 36
Number 4 is 23 units.
I hope I was of assistance!
~ Fire
Answer:
Step-by-step explanation:
Given that Darcie wants to donate minimum 3 blankets to donate to a homeless shelter. No of days left =60
No of days to complete one blanket = 1/(1/15) = 15 days
Hence in 60 days she has to complete ≥3 blankets
No of days she has to utilize for this will be ≥3(15)=45
No of days she can skip crocheting ≤15
Let x be the no of days crocheted and y no of days skipped
Then x+y≤60
See the graph attached as x axis for days crocheted and y for days skipped
No of blankets can be either 3 or 4.