The summand (R?) is missing, but we can always come up with another one.
Divide the interval [0, 1] into 
subintervals of equal length 
:
![[0,1]=\left[0,\dfrac1n\right]\cup\left[\dfrac1n,\dfrac2n\right]\cup\cdots\cup\left[1-\dfrac1n,1\right]](https://tex.z-dn.net/?f=%5B0%2C1%5D%3D%5Cleft%5B0%2C%5Cdfrac1n%5Cright%5D%5Ccup%5Cleft%5B%5Cdfrac1n%2C%5Cdfrac2n%5Cright%5D%5Ccup%5Ccdots%5Ccup%5Cleft%5B1-%5Cdfrac1n%2C1%5Cright%5D)
Let's consider a left-endpoint sum, so that we take values of 
where 
is given by the sequence
with 
. Then the definite integral is equal to the Riemann sum
Answer:
Numbers of pitchers of lemonade = 8
Step-by-step explanation:
Given as
Amount of lemonade concentration = 
of a cup
Now, 
of a cup of concentration mix with 
of water
So, - = 
of cup of lemonade,
∴ The number of small pitcher of lemonade = 
= 4 × 2 = 8 Answer
Answer:
y = 3
Step-by-step explanation:
The y-coordinate of all points on the graph is 3.
The equation is y = 3
