The dimensions of expensive television is 32 inches through 64 inches.
This trouble may be solved if we understand the idea of fraction and a way to calculate the part of a fragment.
right here it is for the reason that the inexpensive tv is 12 inches by means of 24 inches.
Also it is given that the expensive television is
of the cheaper one.
Now taking the length into consideration the length of the television is
=
= 32 inches
Now taking the width into consideration the width of the television is
=
= 64 inches
So, the dimension of the expensive television is 32 inches by 64 inches.
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Answer:
=24m/12m
=2m
Step-by-step explanation:
24m /12m
=2m
Answer:
15 nickels were there with Alexis
Step-by-step explanation:
Let there be x nickels
given that
The number of dimes is 5 less than twice the number of nickels.
no of dimes in terms of x = 2*number of nickels - 5 = 2x - 5
we know that
value of 1 nickel = 5 cents
then
value of x nickel = 5*x cents = 5x cents
we know that
value of 1 dime = 10 cents
then
value of 2x-5 dime = 10(2x - 5) cents = 20x - 50 cents
Total value of x nickel and 2x -5 dimes = 5x + 20x - 50 = 25x - 50
given that
Alexia has total of $3.25 in nickel and dimes thus 25x - 50 must be equal to $3.25
$1 = 100 cents
$3.25 = 3.25 * 100 cents = 325 cents
Thus,
25x - 50 = 325
25x = 325 + 50 = 375
x = 375/25 = 15
Thus, no of nickels = x = 15 answer
b.
You can visit your bank account online and electronically transfer funds to pay your bills.
Probability of distinct 3-digits is 1/6.
Probability of both the first digit and the last digit are even numbers is 1/5.
<u>Step-by-step explanation</u>:
Given set of numbers {1,2,3,5,8,9} = 6
Total number of 3-digits can be formed = 6
5
4 = 120.
<u>Probability of the three-digit numbers with distinct digits</u> :
The number of 3-digit numbers with distinct digits = (6
5
4) / (3
2
1) = 20.
P(distinct 3-digits) = no. of distinct 3-digits / Total no.of 3-digits
⇒ 20/120
⇒ 1/6
<u>Probability that both the first digit and the last digit of the three-digit number are even numbers</u> :
The even numbers in the set are 2 and 8 = 2 possibilities.
The number of 3-digits with 1st and 3rd digit are even = (2
6
2) = 24.
P(1st and 3rd digits even)= no. of 1st and 3rd digit even/Total no. of 3-digits.
⇒ 24/120
⇒ 1/5